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vredina [299]
3 years ago
15

Which number is the smallest? A) 1.28 x 10-4 Eliminate B) 2.85 x 10-6 C) 3.24 x 10-5 D) 5.48 x 10-8

Mathematics
2 answers:
statuscvo [17]3 years ago
7 0
D u doing beachmark test XD GOODLUCK
vfiekz [6]3 years ago
6 0
The answer is D 5.48*10-8 

hope this helps
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Estimate √38.7 to the nearest integer
Murljashka [212]
Well 6^2 is 36 so my best estimate is 6
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Mary ate 5 slices of pie. Arther ate 2 slices. If Mary ate 5/10 of the pie and all the slices werethe same size, what fraction o
viktelen [127]
5/10 +2/10= 7/10 10/10-7/10= 3/10
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Round 8 5/6 to the nearest whole number
kiruha [24]

Answer:

9

Step-by-step explanation:

8 5/6

5/6 is close to 1 so it will round up

8+1 = 9

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Plz help i need this soon​
wlad13 [49]

Answer:

b= (m)(-150)

Step-by-step explanation:

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450/3 = 150

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7 0
3 years ago
A certain manufacturing plant produces electric fuses of which 20% are defective. Find the probability that in a sample of 8 fus
OverLord2011 [107]

Answer:

0.419

Step-by-step explanation:

To calculate this, we shall make use of Bernoulli approximation of Binomial distribution

if 20% are defective, then 80% are not defective

Probability of selecting a defective fuse is 20/100 = 0.2

Probability of selecting a non defective one is 0.8

Probability of at least 1 being defective is = 1 - Probability of none being defective

Mathematically that will be;

0.8^8 = 0.168

The above is probability of none defective

So the probability of at least one will be

1 - 0.168 = 0.832

Probability of not more than 1 means;

Probability of none + probability of 1 being defective

We already have probability of none above

Probability of 1 being defective means 8 will be non defective

The probability in this case is;

8 C 1 0.2^1 0.8^7

= 8 * 0.2 * 0.8^7 = 0.336

Add this to the probability of none = 0.336 + 0.168 = 0.504

So the probability that we want to calculate from the question will be;

Probability of at least one defective * probability of not more than one defective

= 0.832 * 0.504 = 0.419

6 0
3 years ago
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