Answer:
Yes we can conclude.
Step-by-step explanation:
The sampling distribution of 
can be approximated as a Normal Distribution only if:
np and nq are both equal to or greater than 10. i.e.
Both of these conditions must be met in order to approximate the sampling distribution of as Normal Distribution.
From the given data:
n = 50
p = 0.80
q = 1 - p = 1 - 0.80 = 0.20
np = 50(0.80) = 40
nq = 50(0.20) = 10
This means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution
Answer:
Firstly, rewrite the equation:
⅓ (18 + 27) = 81
Substitute x for the given number of it's supposed equivalent.
In this case x = 12.
⅓ (18(12) + 27) = 81
Solve using PEMDAS and simplify what is in the parenthesis first. Then, multiply.
(18 x 12) + 27 = 243
Now, solving using PEMDAS, multiply the total of what you got that was originally in the parenthesis by ⅓ .
⅓ (243) = 81
When you multiple these number they are equivalent to 81.
81 = 81
Since the equation given, when substituted x for 12, is equivalent to 81, this proves that substituting x for 12 makes this equation true.
Answer:
Step-by-step explanation:
You may have entered the measure of a side as the measure of an angle.
You are correct. Good job!
A number raised to an exponent is that number multiplied by itself that number of times.
17^3 = 17 x 17 x 17 = 4913
The answer is B.
Answer:
32.75
Step-by-step explanation:
