Answer:
a. Side lengths of ΔBEX are;
BE = 15 ft.
EX = 12 ft.
BX = 9 ft.
b. Side lengths of XEFY are;
XY = 6 ft.
EX = 12 ft.
FY = 7.5 ft.
EF = 7.5 ft.
c. Side lengths of YFGZ are;
GZ = 6 ft.
FY = 7.5 ft.
YZ = 2 ft.
FG = 2.5 ft.
d. Side length of triangle ZGC
GZ = 6 ft.
GC = 10 ft.
ZC = 8 ft.
Step-by-step explanation:
The given parameters are;
XY : YZ : ZC is 3 : 1 : 4
The length of BC = 25 in.
The length of EB = 15 in.
Therefore, EC = √(BC² - EB²) = √(25² - 15²) = √400 = 20 in.
Given that EX║ YF║GZ, we have;
EF : FG : GC is 3 : 1 : 4 (Parallel lines cut segments in equal proportions)
Therefore;
EF = 20 × 3/(3 + 1 + 4) = 7.5 ft.
FG = 20×1/8 = 2.5 ft.
GC = 20×4/8 = 10 ft.
EC/EX = BC/EB
20/EX = 25/15
EX = 15×20/25 = 12 ft.
XC = √(EC² - EX²) = √(20² - 12²) = 16
XY : YZ : ZC is 3 : 1 : 4
Therefore;
XY = 16 × 3/8 = 6 ft.
YZ = 16 × 1/8 = 2 ft.
ZC = 16 × 4/8 = 8 ft.
GZ = √(GC² - ZC²) = √(10² - 8²) = 6
Area of triangle ΔZGC = 1/2×6×8 = 24 ft²
XB = BC - XC = 25 - 16 = 9 ft.
Area of ΔBEX = 1/2×9×12 = 54 ft²
a. Side lengths of ΔBEX are;
BE = 15 ft.
EX = 12 ft.
BX = 9 ft.
FY = √(FC² - YC²) = √((10 + 2.5)² - (8 + 2)²) = 7.5 ft.
Area of YFGZ = (GZ + FY)/2 × YZ = (6 + 7.5)/2 × 2 = 13.5 ft²
Area of YFGZ = 13.5 ft²
Area of XEFY = XY × (EX + FY)/2 = 6 × (12 + 7.5)/2 = 58.5 ft.²
b. Side lengths of XEFY are;
XY = 6 ft.
EX = 12 ft.
FY = 7.5 ft.
EF = 7.5 ft.
c. Side lengths of YFGZ are;
GZ = 6 ft.
FY = 7.5 ft.
YZ = 2 ft.
FG = 2.5 ft.
d. Side length of triangle ZGC
GZ = 6 ft.
GC = 10 ft.
ZC = 8 ft.
