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2 years ago

Good afternoon guys...

Mathematics

2 answers:

Crazy boy [7]2 years ago

5 0

The reciprocal of 0 is 1/0

We know that it's impossible to divide by 0.

The numbers 2/2 and 1/1 .. are their own reciprocals.

The reciprocal of -5 is 1/5.

2. Rational numbers:

2/4, 3/5, 3/7, 4/2, 4/3

-3/3, -3/4, 1/2, 1/4, 1/7.

A rational number is a fraction. Something my Acellus Algebra I teacher told me:

Rational numbers are fractional.

32^2=32*32=1,024

46^2=46*46=2,116

Square root:

$\sqrt{2304}$

$\sqrt{529}$

Hope it helps!

yarga [219]2 years ago

3 0

Step-by-step explanation:

Blue brackets denote answers

All the best

hope it helps

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For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

Sam borrows $5700 at 4.5% simple interest for 3 years. Find the interest

kherson [118]

Answer:

The interest is

Step-by-step explanation:

Simple interest is given by

$I = \frac{P \times R \times T}{100}$

where

P is the principal

R is the rate

T is the time given

From the question

The principal / P = $ 5700

The rate / R = 4.5%

The time given / T = 3 years

So the interest is

$I = \frac{5700 \times 4.5 \times 3}{100}$

$I = \frac{76950}{100}$

We have the final answer as

I = $ 769.50

Hope this helps you

3 0

3 years ago

How many ways are there to arrange 7 distinct red and 5 distinct blue balls in a row such that no two blue balls are next?

dybincka [34]

18 different ways you could place them<span />

7 0

3 years ago

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A blue die and a red die are thrown. B is the event that the blue comes up with a 6. E is the event that both dice come up even.

iVinArrow [24]

Answer:

Size of |E n B| = 2

Size of |B| = 1

Step-by-step explanation:

<em>I'll assume both die are 6 sides</em>

Given

Blue die and Red Die

Required

Sizes of sets

- $|E\ n\ B|$

- $|B|$

The question stated the following;

B = Event that blue die comes up with 6

E = Event that both dice come even

So first; we'll list out the sample space of both events

$B = \{6\}$

$E = \{2,4,6\}$

Calculating the size of |E n B|

$|E n B| = \{2,4,6\}\ n\ \{6\}$

$|E n B| = \{2,4,6\}$

<em>The size = 3 because it contains 3 possible outcomes</em>

Calculating the size of |B|

$B = \{6\}$

<em>The size = 1 because it contains 1 possible outcome</em>

8 0

3 years ago

Hey! pls help i’ll give brainliest

grandymaker [24]

Answer:

landslide

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers