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atroni [7]
3 years ago
11

Mathematics of inequality

Mathematics
1 answer:
Lady_Fox [76]3 years ago
8 0

Answer:

(-3x²+5x-2)-2(x²-2x-1)

-3x²+5x-2-2x²+2x+2

-5x²+7x

b = 7

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Consider random samples of size 50 from a population with proportion 0.15
WITCHER [35]

Answer:

a) Mean = 0.75

b) Standard error = 0.051

c) Yes                              

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 50

Sample proportion , p = 0.15

a) Mean

\mu = np = 50(0.15) = 7.5

b) Standard error

S.E = \sqrt{\dfrac{p(1-p)}{n}} = \sqrt{\dfrac{0.15(1-0.15)}{50}} = 0.051

c) Application of central limit theorem

Since the sample size is larger than 30, we cam apply central limit theorem for normal approximation.

6 0
4 years ago
4y = 12x - 4<br><br>please show work
xxTIMURxx [149]
Hey!~

The simplified version of this equation in slope-intercept form would be y=3x-1.
"M" is commonly used for the slope.
"B" is used for the x-intercept.

In this equation, 3 is the slope (m), and -1 is the x-intercept (b).

Hope this helps and have a great day!

-Lindsey

7 0
3 years ago
What number (n) must be inserted into the number 3n,85n for it to be divisible by 6?
Dima020 [189]
<span>N = number that must be inserted in the given numbers to be divisible by 6
=> 3n
=> 85n
Now, let’s find a best number that will multiplied with both given number and is divisible with 6.
=> 85n / 6
=> 85(6) / 6
=> 510 / 6
=>n =  6
now, let’s try to 3
=> 3(6) / 6
=> 18 / 6
=> 3
Thus, the value of N is 6 because it is divisible by 6 when multiplied to the given number.

</span>



5 0
4 years ago
IF ANYONE CAN HELP Evaluate x + (-19) for x = 44
Goshia [24]

44+(-19)=25

Reasoning: Just subtract 19 from 44 resulting in 25.

ANSWER: 25

5 0
3 years ago
Carbon-14 is a radioactive isotope that has a half-life of 5,730 years. Approximately how many years will it take for carbon-14
PilotLPTM [1.2K]

Answer:

<em>Carbon-14 will take 19,035 years to decay to 10 percent.</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay.

An exponential decay can be described by the following formula:

N(t)=N_{0}e^{-\lambda t}

Where:

No  = The quantity of the substance that will decay.

N(t) = The quantity that still remains and has not yet decayed after a time t

\lambda     = The decay constant.

One important parameter related to radioactive decay is the half-life:

\displaystyle t_{1/2}=\frac {\ln(2)}{\lambda }

If we know the value of the half-life, we can calculate the decay constant:

\displaystyle \lambda=\frac {\ln(2)}{ t_{1/2}}

Carbon-14 has a half-life of 5,730 years, thus:

\displaystyle \lambda=\frac {\ln(2)}{ 5,730}

\lambda=0.00012097

The equation of the remaining quantity of Carbon-14 is:

N(t)=N_{0}e^{-0.00012097\cdot t}

We need to calculate the time required for the original amout to reach 10%, thus N(t)=0.10No

0.10N_o=N_{0}e^{-0.00012097\cdot t}

Simplifying:

0.10=e^{-0.00012097\cdot t}

Taking logarithms:

ln 0.10=-0.00012097\cdot t

Solving for t:

\displaystyle t=\frac{log 0.10}{-0.00012097}

t\approx 19,035\ years

Carbon-14 will take 19,035 years to decay to 10 percent.

6 0
3 years ago
Read 2 more answers
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