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Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

By substitution, we have that

and

.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
Answer:
L = 25
Step-by-step explanation:
Let's call the Length x and width x - 15 since the width is 15 less than length
Eric needs 70 of fencing in total, the perimeter of a rectangle is calculated by adding all sides
x + x + (x - 15) + (x - 15) = 70 add like terms
4x - 30 = 70 add 30 to both sides
4x = 100 divide both sides by 4
x = 25
Answer:
i have solved them . if u can't understand. .. ask me XD
We need to simplify this number. We begin by evaluating the numbers inside the equation. We can simplify this to:

Now, we evaluate this one step further. Because a negative exponent makes the number 1 over what it was, we can make this problem:

This becomes:

So, 1/4k is the answer. This is the same as C, so C is the right answer.