For the above equation and given zeros of polynomial equation we have;
y=(x+2)(x-3)(x+4)
y=(x^2+2x-3x-6)(x+4)
y=(x^2-x-6)(x+4)
y=(x^3-x^2-6x+4x^2-4x-24)
y=x^3+3x^2-10x-24
Therefore our answer is 3
Hope this helps. Any questions please just ask. Thank you.
Answer: 3
Step-by-step explanation:
For this case we must solve each of the equations proposed:
A) 
We apply distributive property to the terms within parentheses:

Subtracting 6 from both sides of the equation we have:

Dividing between -12 on both sides of the equation:

B) 
We apply distributive property to the terms within parentheses:

We add 5m on both sides of the equation:

Dividing between 2 on both sides of the equation:

C) 
We apply distributive property to the terms within parentheses:

We subtract 14 from both sides of the equation:

Dividing between -7 on both sides of the equation:

D) -
We apply distributive property to the terms within parentheses:

We add 28 to both sides of the equation:

Dividing between -21 on both sides of the equation:

Answer:

Answer:
Answer is 81y^4z^4
Step-by-step explanation:
The expression is (-3yz) (-3yz) (-3yz) (-3yz).
Since all the four terms have power 1:
(-3yz)^1 (-3yz)^1 (-3yz)^1 (-3yz)^1
We know that we can add the powers if the terms have same base
So,
=(-3yz)^1+1+1+1
=(-3yz)^4
=(-3)^4(y)^4(z)^4.
If the power is an even number than the negative sign changes into positive sign.
=3^4y^4z^4
=81y^4z^4
Thus the answer is 81y^4z^4....