1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
Answer:
It is true.
Step-by-step explanation:
congruent polygons have the exact same size and are a perfect match because all corresponding parts are congruent (equal). ... This means that if two polygons are similar, then their corresponding angles are congruent
Answer:
1/3
Step-by-step explanation:
If you're talking about a 6-sided die, then there are 6 sides. Rolling a 2 or a 3 would be a 2/6 chance. To simplify if from there, you can also say that there is a 1/3 chance.
Answer:
Step-by-step explanation:
Given,
Vertex (h, k ) = (1,0)
Now,
We know,
f(x) = a(x-h)²+k
Since, it passess through (2, −17)
Put x = 2 and y = - 17
or, -17 = a(2 - 1)² + 0
or, -17 = a
Now,
f(x) = a(x - h)² + k
= -17(x - 1)² + 0
= -17x² + 34x - 17
