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Oksana_A [137]
2 years ago
14

Martin sorted the bolts in his toolbox by size they measured 3/8in 1/2in 5/8in 7/8in 1 4/8in what is the difference in length be

tween the longest bolt and the shortest bolt
Mathematics
1 answer:
blsea [12.9K]2 years ago
5 0
The longest bolt is 1 4/8 inches, and the shortest bolt is 3/8 inch.

Subtract 3/8 from 1 4/8 to get 1 1/8 inch difference.
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Aaliyah is a salesperson who sells computers at an electronics store. She makes a base
hjlf

Answer:

P=1.25x+70

Step-by-step explanation:

So we know that Aaliyah earns $1.25 commission for every computer she sells. No matter what, she will make $70 per day, so that would be our constant. The $1.25 would be our independent variable since it can change depending on the amount of computers x she sells. Therefore, our equation is:

P=1.25x+70

P represents the total pay, 1.25x represents the total commission for x computers, and the 70 is the base pay.

And we're done!

6 0
3 years ago
Hello, I'm new to homeschooling and I have a question. Do teachers approve of this answer??? I don't know what happens when I su
snow_lady [41]

Answer:my mom said yes shes my teacher

4 0
3 years ago
Read 2 more answers
Bruce’s dumbbells weigh 9 pounds each. If Bruce has 18 dumbbells , how many pounds do they weigh altogether ?
otez555 [7]

To do this, multiply 9 by 18.  This will show you how much they all weigh if there are 18 and each is 9 pounds.


The answer is 162.


Hope this helps!

7 0
3 years ago
Read 2 more answers
Consider a left-tailed test, where the p-value is found to be 0.10. If the sample size n for this test is 49, then the t statist
tigry1 [53]

Answer:

df=n-1=49-1=48  

We know that the p value is 0.1, and since is a left tailed test would be given by:

p_v = P(t_{48} < t_{calculated})=0.1

And we can find the calculated value using excel or the t table.

If we use the following excel code we got: "=T.INV(0.1,48)"

And the calculated value is t_{calculated}=-1.29944

Step-by-step explanation:

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the true mean is lower than specified valu \mu_o, the system of hypothesis would be:  

Null hypothesis:\mu \geq \mu_o  

Alternative hypothesis:\mu < \mu_o  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can find the degrees of freedom for this test given by:

df=n-1=49-1=48  

We know that the p value is 0.1, and since is a left tailed test would be given by:

p_v = P(t_{48} < t_{calculated})=0.1

And we can find the calculated value using excel or the t table.

If we use the following excel code we got: "=T.INV(0.1,48)"

And the calculated value is t_{calculated}=-1.29944

3 0
2 years ago
Kindly answer this question it would be really helpfull
Svetach [21]

Answer:

The values in the table, taking into account the quadratic equation, are:

  • x     -3     -2     -1     0     1     2     3     4
  • y     <u>16</u>      9     <u>4</u>     1     <u>0</u>     1     <u>4</u>     9

Step-by-step explanation:

To obtain the values of the table, you must use the quadratic equation given:

  • <u>y = x^2 - 2x + 1</u>

Now, you must replace the x with the one that is above the value you want to find, in the first case, we're gonna replace the value x with -3:

  • y = x^2 - 2x + 1
  • y = (-3)^2 - 2*(-3) + 1
  • y = 9 + 6 + 1
  • <u>y = 16</u>

When x is -1

  • y = x^2 - 2x + 1
  • y = (-1)^2 - 2*(-1) + 1
  • y = 1 + 2 + 1
  • <u>y = 4</u>

When x is 1

  • y = x^2 - 2x + 1
  • y = (1)^2 - 2*(1) + 1
  • y = 1 - 2 + 1
  • <u>y = 0</u>

When x is 3:

  • y = x^2 - 2x + 1
  • y = (3)^2 - 2*(3) + 1
  • y = 9 - 6 + 1
  • <u>y = 4</u>

At last, the graph must be as the attached picture I give you, but <u><em>remember in y-axis you must use 1 cm as unit and in the x-axis you must use 2 cm as unit, in this form, the graph will not be so elongated as the picture I attach, It would be wider</em></u>.

3 0
2 years ago
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