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irga5000 [103]
3 years ago
10

What is the square of the imaginary number 3i?

Mathematics
2 answers:
Gwar [14]3 years ago
8 0

Answer:

-9

Step-by-step explanation:

Illusion [34]3 years ago
5 0
−
9
Explanation:
(
3
i
)
2
=
9
i
2
i
2
=
−
1
,
therefore,
9
i
2
=
9
⋅
(
−
1
)
=
−
9
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What is 8/10 divided by 1 5/6
sveta [45]
1st change 1 5/6 into a mixed number:
1 5/6 = 11/6

New problem:
8/10 divided by 11/6

to divide fractions you turn the 1st fraction upside down and then change the division sign to a multiplication sign:

8/10 / 11/6
10/8 * 11/6
=55/24 or 1 7/24
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3 years ago
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The two shorter sides of a triangle are 9 and 12. what is a possible length to make length of the third side to make the triangl
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The two shorter sides of triangle are 9 and 12. what is a possible length to make length of the third side to make the triangle acute with acuteT
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What decimal is equivalent to negative 3 over 8
timurjin [86]

Answer:

-9 / 24

Step-by-step explanation:

<u>Step 1:  Find an equivalent to -3/8</u>

(-3*3) / (8*3)

<em>-9 / 24</em>

<em />

Answer:  -9 / 24

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Given matrices A and B shown below, find (3)A+(8)B.
Tasya [4]

Answer:

\left[\begin{array}{ccc}32&-55\\3&39\end{array}\right]

Step-by-step explanation:

\left[\begin{array}{ccc}0&-15\\3&15\end{array}\right] +\left[\begin{array}{ccc}32&-40\\0&24\end{array}\right] =\left[\begin{array}{ccc}0+32&-15+(-40)\\3+0&15+24\end{array}\right] = \left[\begin{array}{ccc}32&-55\\3&39\end{array}\right]

5 0
3 years ago
Consider the following functions. f1(x) = x, f2(x) = x2, f3(x) = 2x − 4x2 g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, a
bekas [8.4K]

9514 1404 393

Answer:

  • (c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
  • NOT linearly independent

Step-by-step explanation:

We want ...

  c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0

Substituting for the fn function values, we have ...

  c1·x +c2·x² +c3·(2x -4x²) ≡ 0

This resolves to two equations:

  x(c1 +2c3) = 0

  x²(c2 -4c3) = 0

These have an infinite set of solutions:

  c1 = -2c3

  c2 = 4c3

Then for any parameter t, including the "trivial" t=0, ...

  (c1, c2, c3) = (-2t, 4t, t)

__

f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)

7 0
2 years ago
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