The answer would be A. Make sure you also use BEDMAAS, and take care of the brackets first
Answer:
Step-by-step explanation:
m ∠XOY = m ∠WOV
so, m XY = m WV --- (i)
{ If angle subtended by two arcs at the center are equal, then length of arc are equal}
m YZ = m ZW ------- (ii) {given}
Add (i) and (ii)
XY + YZ = WV + ZW
XZ = ZV
Hence proved.
Answer:
w = 3
Step-by-step explanation:
-6(w - 4) + 8W=6(w + 2)
-6w + 24 + 8w = 6w + 12
2w + 24 = 6w + 12
12 = 4w
3 = w
Answer:
domain: 0 - 10 range: 0 - 32
Step-by-step explanation:
Take the lowest x and the highest x and put them in set values to get domain.
lowest x = 0 and highest x = 10.
Take the lowest y and the highest y and put them in set values to get range.
lowest y = 0 and highest y = 32
Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261%5C%5C-2%261%260%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%265%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D)

So the value of the element in the position
is 15

So the value of the element in the position
is 14
Then with these two values you can determinate the result matrix.
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)