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mariarad [96]
4 years ago
7

If one bag of topsoil covers 10 square feet, how many bags are needed to cover this flowr bed?

Mathematics
2 answers:
Nataly [62]4 years ago
8 0
3 bags are needed to cover the flower bed.
Katyanochek1 [597]4 years ago
3 0

Answer:

3 bags are needed to cover this flower bed

Step-by-step explanation:

Use conversion:

1 yard = 3 feet

Area of a triangle(A) is given by:

A = \frac{1}{2}bh

where,

b is the base and h is the height of the triangle.

As per the statement:

From the given diagram:

Base(b) = 3 yards = 9 feet

Height(h) = 2 yard = 6 feet

then;

A = \frac{1}{2} \cdot 6 \cdot 9 = 3 \cdot 9 = 27 square feet.

Since, it is given that if one bag of topsoil covers 10 square feet

⇒10 square feet =  1 bag

then\;

in 27 square feet = \frac{27}{10} = 2.7 \approx 3 bag

Therefore, 3 bags are needed to cover this flower bed

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Answer: 128 inches

Step-by-step explanation:

let's start with the perimeter: the perimeter is the total length to the sides/edges of a shape.

since we're dealing with a rectangle, there will be 4 sides

two lengths & two widths

so 48+48+16+16=128 inches

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4 years ago
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Solve 2(b − 3) ≥ 3(3 − b) and describe the graph of the solution. Show all your work.
solong [7]

Answer:

\large\boxed{b\geq3\to b\in[3,\ \infty)}

Step-by-step explanation:

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4 0
3 years ago
A city hosted a music festival that included three concerts. According to the sales database, 28% of the audience attended the f
Vitek1552 [10]

Answer:

P(X\cap Y\cap Z)=0.05

Step-by-step explanation:

From the question we are told that:

Percentage of audience in first concert P(X)=0.28

Percentage of audience in second concert P(Y)=0.42

Percentage of audience in third concert P(Z)=0.30

Audience Percentage at at-least one concert P(X \cup Y \cup Z)=0.80

Percentage of audience at first & second concert P(X \cap Y)=0.10

Percentage of audience in first & third concert P(X \cap Z)=0.08

Percentage of audience in second & third concert P(Y\cap Z)=0.07

 

Generally the equation for probability of attending all concerts P(X\cap Y\cap Z)is mathematically given by

P(X \cup Y \cup Z)=P(X)+P(Y)+P(Z)-P(X \cap Y)-P(X \cap Z)-P(Y\cap Z)+P(X\cap Y\cap Z)

P(X\cap Y\cap Z)=P(X \cup Y \cup Z)-P(X)-P(Y)-P(Z)+P(X \cap Y)+P(X \cap Z)+P(Y\cap Z)

P(X\cap Y\cap Z)=0.80-0.28-0.42-0.30+0.10+0.80+0.70

P(X\cap Y\cap Z)=0.05

Therefore the probability that a randomly selected audient attended all the concerts

P(X\cap Y\cap Z)=0.05

8 0
3 years ago
What is x? Please help fast
Firdavs [7]

Answer:

x = 47°

Step-by-step explanation:

m∠DPB + ∠BPC = 180° (Definition of a straight line)

Plug in the corresponding numbers and variables to the corresponding places:

x + 133 = 180

Isolate the variable, x. Subtract 133 from both sides:

x + 133 (-133) = 180 (-133)

x = 180 - 133

x = 47

47° is your answer.

~

3 0
3 years ago
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