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3 years ago

13

An electric can opener is worth 36 dollars when it is new. After each year, it is worth half what it was the previous year. What

will it's worth be after 8 years? Round your answer to the nearest cent. Write the model.

1 answer:

Likurg_2 [28]3 years ago

4 0

So the equation is f(x)=36*(.5)^8, since your principal worth is 36 and it depreciates by 1/2 each year, which is 14 cents.

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* There are five cars in line at a stoplight. Each of these cars is a different color and different type of car. Diego is drivin

Svetach [21]

Info given :
vehicles : (colors)red car, green car, yellow car, blue car, white car
types : sedan, minivan, SUV, convertible, pick-up truck
people : Diego, Ingrid, Rachel, Anton, Yuna

Diego -- red car -- minivan -- 3rd car
Ingrid -- white car -- sedan -- 4th car
Yuna -- green car -- truck -- 5th car
Rachel -- yellow car -- SUV -- 1st car
Anton -- blue car -- convertible -- 2nd car

I am thinking the truck, it is green, is driven by Yuna

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3 years ago

The cheerleader section is on the basketball court. Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards. How man

Lady_Fox [76]

Answer:

The area of the floor space is equal to 5.83 sq yards.

Step-by-step explanation:

Given that,

Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards.

We need to find how many square yards of floor space are taken up by one row of cheerleaders.

We know that, the area of a rectangle is given by :

A = lb

So,

$A=\dfrac{7}{4}\times \dfrac{10}{3}\\\\A=5.83\ yards^2$

So, the area of the floor space is equal to 5.83 sq yards.

5 0

3 years ago

The standard form of the equation for a quadratic function is, with he vertex of the graph of the function at the point (p,q). t

ludmilkaskok [199]

Answer:

p = ½ (x₁ + x₂)

q = a (x₁x₂ − ¼ (x₁ + x₂)²)

Step-by-step explanation:

y = a (x − x₁) (x − x₂)

Expand:

y = a (x² − x₁x − x₂x + x₁x₂)

y = a (x² − (x₁ + x₂)x + x₁x₂)

Distribute a to the first two terms:

y = a (x² − (x₁ + x₂)x) + ax₁x₂

Complete the square:

y = a (x² − (x₁ + x₂)x + ¼(x₁ + x₂)²) + ax₁x₂ − ¼ a(x₁ + x₂)²

y = a (x − ½ (x₁ + x₂))² + a (x₁x₂ − ¼ (x₁ + x₂)²)

Therefore:

p = ½ (x₁ + x₂)

q = a (x₁x₂ − ¼ (x₁ + x₂)²)

3 0

3 years ago

PLEASE HELP ILL GIVE BRAINLIEEST<br> SHOW WORK

Genrish500 [490]

You know that it's a bot when it says "explanation in file".

They forgot to put a question, there's nothing to answer...

8 0

3 years ago

For what value of constant c is the function k(x) continuous at x = 0 if k =

nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:

$\mathbf{ \lim_{x \to 0^-} k(x) = \lim_{x \to 0^+} k(x) = 0 }$

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= c }$

Provided that:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }$

Using l'Hospital's rule:

$\mathbf{\implies \lim_{x \to 0} \ \ \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}= \lim_{x \to 0} sec \ x \ tan \ x = 0}$

Therefore:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}=0 }$

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

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2 years ago