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tensa zangetsu [6.8K]
3 years ago
5

Write a program that can print a banner with rotated letters, such that they can be read from top to bottom. Specifically, each

letter in the message should be printed using multiple lines composed of * symbols. The code to print each letter should go into a separate method just for that letter (no parameters, no return value). Don’t worry, you don’t need to make 26 different methods, just 8: the seven letters in the message "Hello World" (D, E, H, L, O, R, and W) and a space. In your main method, you should ask the user to type a message. Then, loop through each character in the message and, for each character, if you have a corresponding method, call the method to print out the letter to the screen, ignoring any other characters. To help get you started, here is an example method for the letter D:
Computers and Technology
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

package Lab6Problema;

import java.util.Scanner;

public class Lab6Problema{

public static void H() // prints H

{

System.out.println();

System.out.println("** **");

System.out.println("** **");

System.out.println("******");

System.out.println("** **");

System.out.println("** **");

}

 

public static void E()//prints E

{

System.out.println();

System.out.println("******");

System.out.println("** ");

System.out.println("******");

System.out.println("** ");

System.out.println("******");

}

 

public static void L()//prints L

{

System.out.println();

System.out.println("* ");

System.out.println("* ");

System.out.println("* ");

System.out.println("* ");

System.out.println("******");

}

 

public static void O()//prints O

{

System.out.println();

System.out.println("******");

System.out.println("* *");

System.out.println("* *");

System.out.println("* *");

System.out.println("******");

}

 

public static void W()//prints W

{

System.out.println();

System.out.println("* *");

System.out.println("* *");

System.out.println("* ** *");

System.out.println("* ** *");

System.out.println("** **");

}

 

public static void R()//prints R

{

System.out.println();

System.out.println("***** ");

System.out.println("** **");

System.out.println("***** ");

System.out.println("** **");

System.out.println("** **");

}

 

public static void D()//prints D

{

System.out.println();

System.out.println("**** ");

System.out.println("* * ");

System.out.println("* *");

System.out.println("** * ");

System.out.println("**** ");

}

public static void blank() //prints blank space

{

System.out.println();

System.out.println();

System.out.println();

}

public static void main(String[] args) {

//just enter "Hello World" as input as specified

System.out.println("Enter a Message");

Scanner scan=new Scanner(System.in);

String myMessage=scan.nextLine(); // read msg using scanner

int numOfCharacters=myMessage.length();// calculate message lenth

for(int i=0;i<numOfCharacters;i++) // loop through each chracter in msg

{

// gets character at position i, and switch accordingly

switch(myMessage.charAt(i))

{

// if character is 'H' or 'h', call method H(). Similarly for other

// Hecharacters in message.

case 'H':

case 'h':H();break;

case 'E':

case 'e':E();break;

case 'L':

case 'l':L();break;

case 'O':

case 'o':O();break;

case 'W':

case 'w':W();break;

case 'R':

case 'r':R();break;

case 'D':

case 'd':D();break;

case ' ':blank();break;

}

}

}

}

Explanation:

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a.Write a Python function sum_1k(M) that returns the sum푠푠= ∑1푘푘푀푀푘푘=1b.Compute s for M = 3 by hand and write
stealth61 [152]

Answer:

def sum_1k(M):

   s = 0

   for k in range(1, M+1):

       s = s + 1.0/k

   return s

def test_sum_1k():

   expected_value = 1.0+1.0/2+1.0/3

   computed_value = sum_1k(3)

   if expected_value == computed_value:

       print("Test is successful")

   else:

       print("Test is NOT successful")

test_sum_1k()

Explanation:

It seems the hidden part is a summation (sigma) notation that goes from 1 to M with 1/k.

- Inside the <em>sum_1k(M)</em>, iterate from 1 to M and calculate-return the sum of the expression.

- Inside the <em>test_sum_1k(),</em> calculate the <em>expected_value,</em> refers to the value that is calculated by hand and <em>computed_value,</em> refers to the value that is the result of the <em>sum_1k(3). </em>Then, compare the values and print the appropriate message

- Call the <em>test_sum_1k()</em> to see the result

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How did machines get involved throughout the years?
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Answer:

Although the primary goal of a political machine is keeping itself in power rather than providing good government, machines have been responsible for restructuring city governments to centralize authority, improving facilities and services, helping to assimilate immigrant groups, and encouraging the growth of business and industry. Supporters of political machines say that they “work” and that consolidating power in the hands of a boss.

Explanation:a political machine is a political group in which an authoritative leader or small group command the support of a corps of supporters and businesses

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Write a c++ program to print even numbers from 1 to 20​
Novay_Z [31]

Answer:

#include <bits/stdc++.h>

using namespace std;

// Function to print even numbers

void printEvenNumbers(int N)

{

cout << "Even: ";

for (int i = 1; i <= 2 * N; i++) {

// Numbers that are divisible by 2

if (i % 2 == 0)

cout << i << " ";

}

}

// Function to print odd numbers

void printOddNumbers(int N)

{

cout << "\nOdd: ";

for (int i = 1; i <= 2 * N; i++) {

// Numbers that are not divisible by 2

if (i % 2 != 0)

cout << i << " ";

}

}

// Driver code

int main()

{

int N = 20;

printEvenNumbers(N);

printOddNumbers(N);

return 0;

}

Explanation:

Note: This will find both odd and even numbers, you have to change the number above to the number of your choice

For even numbers

Even number are numbers that are divisible by 2.

To print even numbers from 1 to N, traverse each number from 1.

Check if these numbers are divisible by 2.

If true, print that number.

For odd numbers

Odd number are numbers that are not divisible by 2.

To print Odd numbers from 1 to N, traverse each number from 1.

Check if these numbers are not divisible by 2.

If true, print that number

8 0
3 years ago
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