Answer:
axial V = 0
equatorial V = k q 2a / (x² -a²), V = k q 2x / (a² -x²)
Explanation:
A dipole is a system formed by two charges of equal magnitude, but different sign, separated by a distance 2a; let's look for the electrical potential in an axial line
V = k (q / √(a² + y²) - q /√ (a² + y²))
V = 0
the potential on the equator
we place the positive charge to the left and perform the calculation for a point outside the dipole
V = k (q / (x-a) - q / (x + a))
V = k q 2a / (x² -a²)
we perform the calculation for a point between the dipo charges
V = k (q / (a-x) - q / (a + x))
V = k q 2x / (a² -x²)
Answer:
Option D.) 0.09 I₀
Explanation:
The intensity, I, of a polarized light after passing through a polarizing filter is given by
Original Intensity
Angle between the direction of polarization and the axis of filter
After passing through the first polarizer, the initial intensity,
is halved, i.e 
After passing through the second polarizer, the angle of polarization, θ = 30⁰


After passing through the third polarizer, the angle of polarization, θ = 90⁰-30⁰ = 60⁰



Explanation:
The total resistance used to calculate the total resistance of the two parallel resistor is given by :

Taking reciprocal of the above equation.

We can also write the above equation as :

On simplification of above equation,

or

Hence, proved.
Answer:
Explanation:
The best way to do this is to remember the rule about the halfway mark in a parabolic path. At a trajectory's half way point in its travels, it will be at its max height. To get the total time in the air, we take that time at half way and double it. Here's what we know that we are told:
initial velocity is 20 m/s
Here's what we know that we are NOT told:
a = -9.8 m/s/s and
final velocity is 0 at an object's max height in parabolic motion.
We will use the equation:
where v is final velocity and v0 is initial velocity. Filling in:
0 = 20 + (-9.8)t and
-20 = -9.8t so
t = 2 seconds. The stone reaches its max height 2 seconds after it is thrown; that means that after another 2 seconds it will be on the ground. Total air time is 4 seconds.
Answer:

Explanation:
Given data:
mass of block is 
radius of block = 0.061 m
moment of inertia is 
D is distance covered by block = 0.65 m
speed of block is 1.705 m/s
From conservation of momentum we have

![0.84 \times 9.81 \times 0.65 = \frac{1}{2}\times 0.84 \times 1.705^2 +\frac{1}{2} \times 6.2 \times 10^{-3} [\frac{1.705}{0.061}]^2 + E_l](https://tex.z-dn.net/?f=0.84%20%5Ctimes%209.81%20%5Ctimes%200.65%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%200.84%20%5Ctimes%201.705%5E2%20%2B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%206.2%20%5Ctimes%2010%5E%7B-3%7D%20%5B%5Cfrac%7B1.705%7D%7B0.061%7D%5D%5E2%20%2B%20E_l)
solving for energy loss
