Answer:
The circular loop experiences a constant force which is always directed towards the center of the loop and tends to compress it.
Explanation:
Since the magnetic field, B points in my direction and the current, I is moving in a clockwise direction, the current is always perpendicular to the magnetic field and will thus experience a constant force, F = BILsinФ where Ф is the angle between B and L.
Since the magnetic field is in my direction, it is perpendicular to the plane of the circular loop and thus perpendicular to L where L = length of circular loop. Thus Ф = 90° and F = BILsin90° = BIL
According to Fleming's left-hand rule, the fore finger representing the magnetic field, the middle finger represent in the current and the thumb representing the direction of force on the circular loop.
At each point on the circular loop, the force is always directed towards the center of the loop and thus tends to compress it.
<u>So, the circular loop experiences a constant force which is always directed towards the center of the loop and tends to compress it.</u>
The source/size of the charge.
The distance from the source of charge.
Answer:
61.105 C
Explanation:
Charge: This can be defined as the product of current flowing through a circuit and time. The S.I unit of charge is coulomb's (C)
I = Q/t ................. Equation 1
Where I = current, Q = Charge, t = time.
Note: The current through a cross sectional area of the compressor is the amount of charge passing through the area per unit time.
Q = It ............... Equation 2
Given: I = 121 A, t = 0.505 A.
Substitute into equation 2
Q = 121(0.505)
Q = 61.105 C.
Hence the charge passing through the cross sectional area of the circuit = 61.105 C
Answer:
The wavelength of the electron is
Explanation:
Given that,
Temperature = 300 K
We know that,
The energy of free electron is
Where, k = wave number
The momentum of the electron is
Th effective mass is
We need to calculate the wavelength of the electron
Using formula of wave number
Put the value of k
We know that,
Thermal energy of electron
The de Broglie wavelength of the electron is
Put the value into the formula
Hence, The wavelength of the electron is