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3 years ago

Do you think an observer on another planet in the solar system might see eclipses

Physics

1 answer:

artcher [175]3 years ago

8 0

Answer:

Yes

Explanation:

Eclipses: Eclipses are also known as game of shadows where one object comes between the star(light source) and another object in a straight line such that the shadow of one object falls on other object. This can occur when the apparent size of the star and the object is almost same.

Talking about the Earth, the geometry is such that the Moon and the Sun are of same apparent size as seen from the Earth. Thus Lunar and Solar eclipse can be seen from the Earth. If we were to go on any other planet the same phenomenon can be seen provided the apparent size of moon and the Sun from that planet is same.

We have seen and recorded many such eclipses on Jupiter. These are from the perspective of Earth. When the moons of Jupiter comes exactly between the Sun and Jupiter the shadow of moon will fall on Jupiter. The places where the shadow falls, one will see a solar eclipse.

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HELP PLEASE NOWWWW !!!! ( 1 ) Jill and Scott both road their bikes for 30 minutes. Jill traveled 5 kilometers and Scott trave

katovenus [111]

Jill and Scott both moves for 30 minutes

now if Jill cover 5 km distance and Scott cover 10 km distance

now we know that the formula of speed is given as

$speed = \frac{distance}{time}$

now we will have

speed of Jill

$v = \frac{5}{0.5} = 10 km/h$

speed of Scott

$v = \frac{10}{0.5} = 20 km/h$

so correct answer here is

Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.

#2

distance travelled by each car is given as

$d = 400 miles$

now here it is given that

time taken by green car

$t_1 = 10 hours$

time taken by yellow car

$t_2 = 8 hours$

now we can find the speed of two cars

$speed = \frac{distance}{time}$

speed of green car

$v = \frac{400}{10} = 40 mph$

speed of yellow car

$v = \frac{400}{8} = 50 mph$

so correct answer will be

The yellow car was faster. Yellow traveled at a speed of 50 mph while green was traveling at an average of 40 mph.

6 0

3 years ago

Read 2 more answers

The effect of gravity on a falling object can be modeled by a ball dropped

weeeeeb [17]

Answer:

B. Friction with air also affects the fall of the object.

Explanation:

The limitation of this experimental design is that friction with air also affects the fall of the object.

Therefore, it is difficult to measure effect of gravity on falling objects.
Air resistance cause friction in the movement of an object falling.
Frictional force resists the motion of an object subject to free fall.

Therefore, the experiment will be biased due to the influence of the frictional force.

5 0

3 years ago

A television channel is assigned the frequency range from 54 MHz to 60 MHz. A series RLC tuning circuit in a TV receiver resonat

Stella [2.4K]

Answer:

A.) L = 0.37 μH B) 7.61 Ω

Explanation:

A) At resonance, the circuit behaves like it were purely resistive , so the reactance value must be 0.

So, the following condition must be met:

ω₀*L = 1/ (ω₀*C) ⇒ ω₀² = 1/LC

We know that, for a sinusoidal source, there exists a fixed relationship between the angular frequency ω₀ and the frequency f₀, as follows:

ω₀ = 2*π*f₀

⇒ (2*π*f₀)² = 1/(L*C)

Replacing by the givens (f₀, C), we can solve for L:

L = 1 /((2*π*f₀)²*C) = 1/(2*π*57*10⁶)² Hz²*21*10⁻¹² f = 0.37 μH

b) At resonance, the current can be expressed as follows:

I₀ = V/Z = V/R

We need to find the minimum value of R that satisfies the following equation:

I = 0.5 I₀ = 0.5 V/R = V/Z

⇒ 0.5/R = 1/√(R²+X²)

Squaring both sides , we have:

(0.5)²/R² = 1/ (R²+X²)

⇒ 0.25 (R²+X²) = R² ⇒ R² = X² / 3

We need to find the value of R that satisfies the requested condition througout the frequency range.

So, we need to find out the value of the reactance X in the lowest and highest frequency, as follows:

Xlow = ωlow * L - 1/(ωlow*C)

⇒ Xlow = ( (2*π*54*10⁶)*0.37*10⁻⁶) - 1/ ((2*π*54*10⁶)*21*10⁻¹²) = -14.81Ω

Xhi = ωhi * L - 1/(ωhi*C)

⇒ Xhi = ( (2*π*60*10⁶)*0.37*10⁻⁶) - 1/ ((2*π*60*10⁶)*21*10⁻¹²) = 13.18Ω

For these reactance values, we can find the corresponding values of R as follows:

Rlow² = Xlow²/3 = (-14.81)²/3 = 75Ω² ⇒ Rlow = 8.55 Ω

Rhi² = Xhi² / 3 = (13.18)²/3 = 56.33Ω² ⇒Rhi = 7.61 Ω

The minimum value of R that satisfies the requested condition is R= 7.61ΩΩ.

3 0

3 years ago

What is the role of pressure and dissolved gases in eruptions?.

Katarina [22]

Answer:

Explanation:

Magma contains dissolved gases, which provide the driving force that causes most volcanic eruptions. As magma rises towards the surface and pressure decreases, gases are released from the liquid portion of the magma (melt) and continue to travel upward, and are eventually released into the atmosphere.

8 0

2 years ago

An electron is a negatively charged particle that has a charge of magnitude, e - 1.60 x 10-19 C. Which one of the following stat

irina [24]

Explanation:

The charge on the electron is, $q=-1.6\times 10^{-19}\ C$

The electric field at a distance r from the electron is :

$E=k\dfrac{q}{r^2}$

Where

k is the electrostatic constant, $k=\dfrac{1}{4\pi \epsilon_o}$

We know that the electric field lines starts from positive charge and ends at the negative charge. Also, for a positive charge the field lines are outwards while for a negative charge the field lines are inwards.

So, the correct option is " the electric field is directed toward the electron and has a magnitude of $k\dfrac{q}{r^2}$ . Hence, this is the required solution.

4 0

3 years ago