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k0ka [10]
3 years ago
7

James has four and three fourths feet of rope he plans to cut off 1 1/2 feet from the Rope how much rope will be left

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
7 0
Well to put it in numbers, he has 4 3/4 feet of rope. He wants to cut off 1 1/2.

First we need to get common fractions. The way we do this is: is there anyway to make a 2, a four? Yes! There is! (If there is not, you have to find the Least common multiple)

How do we make this two a four? we times it by 2! But we have to be nice, and multiply the whole fraction, just to be fair.

So, we now have 4 3/4 rope, and James wants to get rid of 1 2/4 rope.

For starters, lets go easy. He has 4 foot, he wants one gone. So he has 3 feet of rope left.

But we still have the fractions! He has 3/4 rope, and we want to get rip of 2/4! so we subtract the numerators, and are left with 1/4 (its important you remember to keep the denominator in this case!)

So if we combine that, James will be left with 3 1/4 feet of rope!
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The value of mean, standard deviation and interval from the method of tree ring dating is 1273 AD, 37 years, [1250,1296].

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we have to find that the standard deviation, mean and the intervals from the given data.

So, According to the given data from the method of tree ring dating

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x-bar = (1271 + 1208 + 1229 + 1299 + 1268 + 1316 + 1275 + 1317 + 1275) / 9 = x-bar = 1273 AD

And now we find standard deviation :

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∑(xi - x-bar)^2 = (1271 - 1273)2 + (1208 - 1273)2 + (1229 - 1273)2 + ... + (1275 - 1273)2

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∑(xi - x-bar)^2 = 4 + 4225 + 1936 + 676 + 25 + 1849 + 4 1936 + 4

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s^2 = 10659/8 = 1332

s = 37 years

So, standard deviation is 37 years.

We need the t-distribution table since the standard deviation is unknown.  Therefore, our degrees of freedom is 9 - 1 = 8 and the critical value is 1.860.  Set up the confidence interval for the mean:

[x-bar ± t*(s/√n)] = [1273 ± 1.860*(37/√9)]

[x-bar ± t*(s/√n)] = [1250,1296]

So, The value of mean, standard deviation and interval from the method of tree ring dating is 1273 AD, 37 years, [1250,1296].

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