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k0ka [10]
4 years ago
7

James has four and three fourths feet of rope he plans to cut off 1 1/2 feet from the Rope how much rope will be left

Mathematics
1 answer:
Pavlova-9 [17]4 years ago
7 0
Well to put it in numbers, he has 4 3/4 feet of rope. He wants to cut off 1 1/2.

First we need to get common fractions. The way we do this is: is there anyway to make a 2, a four? Yes! There is! (If there is not, you have to find the Least common multiple)

How do we make this two a four? we times it by 2! But we have to be nice, and multiply the whole fraction, just to be fair.

So, we now have 4 3/4 rope, and James wants to get rid of 1 2/4 rope.

For starters, lets go easy. He has 4 foot, he wants one gone. So he has 3 feet of rope left.

But we still have the fractions! He has 3/4 rope, and we want to get rip of 2/4! so we subtract the numerators, and are left with 1/4 (its important you remember to keep the denominator in this case!)

So if we combine that, James will be left with 3 1/4 feet of rope!
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An unopened cereal box contains 15/28 cubic foot of cereal. If the box is full, and the length and height of the box are5/7 and
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So the unsolved equation is:
V = h × l × w

Separate the w by diving both sides by h and l:
w =  \frac{v}{hl}
Then plug in the numbers:
w =  \frac{( \frac{15}{28}) }{( \frac{11}{2} ) \times ( \frac{5}{7}) }
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