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lions [1.4K]
3 years ago
6

Which represents the ionization of a strong eletrolyte

Chemistry
1 answer:
zheka24 [161]3 years ago
3 0

Answer: The answer is K3PO4(s) → 3K+(aq) + PO43–(aq) since water-soluble ionic tripotassium phosphate dissociates completely into K+ and PO43– ions when dissolved, that is, no K3PO4 remains in the solution. Carbonic acid H2CO3 and acetic acid CH3COOH are weak electrolytes since they are weak acids that do not completely ionize, while nonelectrolyte CH3OH do not dissociate into ions.

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How many moles of NaCl are present in 2.50 L of a 0.070 M solution?
posledela

Given :

Volume of NaCl solution 2.5 L .

Molarity of NaCl solution is 0.070 M .

To Find :

How many moles are present in the solution.

Solution :

Let, n be the number of moles.

We know, molarity is given by :

M = \dfrac{n}{V(in\ L)}

So,

n = M \times V\\\\n = 0.070\times 2.5 \\\\n = 0.175\ moles

Therefore, number of moles of NaCl is 0.175 moles.

6 0
3 years ago
Holding temperature and pressure constant, what is the most important feature in determining the phase of a given organic compou
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3 years ago
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Identify these element:a non-metal in the same group as leads?
Basile [38]

Answer:

tin and it is called a carbon group

Explanation:

4 0
3 years ago
Click the "draw structure" button to launch the drawing utility. Propane (CH3CH2CH3) has both 1° and 2° hydrogens. Draw the carb
OlgaM077 [116]

Answer:

a) find attached image 1

b) find attached image 2

Explanation :

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since the bond dissociation for cleavage of the bond to form primary free radical is higher, more energy must be added to form it. This makes primary free radical higher in energy and therefore less stable than secondary free radical.

6 0
3 years ago
What is the ph of a 2.00 m hno2 solution if ka=5.00 e-6?
zysi [14]

Answer: -

2.5

Explanation: -

Initial [HNO₂] = 2.00 M

ka = 5.00 x 10 ⁻⁶

ICE table for HNO₂ =

[\left[\begin{array}{cccc}concentrations&HNO2&H+&NO2\\Initial&2.00&0&0\\Change&-x&+x&+x\\Equilibrium&2.00-x&x&x\end{array}\right]

Ka = \frac{x2}{2.00-x}

5.00 x 10-6 = \frac{x2}{2.00-x}

x = 0.0032 M

pH = - log [H⁺]

= - log 0.0032

= 2.5

6 0
3 years ago
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