Answer:
Ba
Explanation:
Magnesium is the element of second group and third period. The electronic configuration of magnesium is - 2, 8, 2 or
There are 2 valence electrons of magnesium.
Fluorine is the element of seventeenth group and second period. The electronic configuration of fluorine is - 2, 7 or
There is 1 valence electron of fluorine.
They will combine and form 
<u>The same type of compound is formed by the other members of the group 2 since they will have 2 valence electron.</u>
Group 2 includes:- beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra).
Hence, correct options is:- Ba
37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2
<span>4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms</span>
Answer:
The five assumption of Kinetic molecular theory are given below.
Explanation:
Kinetic molecular theory of gasses stated that,
1) Gases consist of large number of smaller particles which are distance apart from each others.
2) The gas molecules collide with each other and also with wall of container and this collision is elastic.
3) Gas molecules are in continuous random motion and posses kinetic energy.
4) The forces of attraction between gas molecules are very small and considered negligible.
5) The temperature of gas is directly proportional to average kinetic energy of gas molecules.
<u>Answer:</u> The volume when the pressure and temperature has changed is 1332.53 L
<u>Explanation:</u>
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law. The equation follows:

where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
We are given:
![P_1=0.950atm\\V_1=200L\\T_1=27^oC=[273+27]K=300K\\P_2=0.125atm\\V_2=?L\\T_2=-10^oC=[273-10]K=263K](https://tex.z-dn.net/?f=P_1%3D0.950atm%5C%5CV_1%3D200L%5C%5CT_1%3D27%5EoC%3D%5B273%2B27%5DK%3D300K%5C%5CP_2%3D0.125atm%5C%5CV_2%3D%3FL%5C%5CT_2%3D-10%5EoC%3D%5B273-10%5DK%3D263K)
Putting values in above equation, we get:

Hence, the volume when the pressure and temperature has changed is 1332.53 L