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34kurt
3 years ago
8

The electrons in an atoms outermost orbitals, the electrons, are represented in a(n) , which consists of the elements symbol, re

presenting the atomic nucleus and inner-level electrons, and the appropriate number of dots.
Chemistry
1 answer:
Elis [28]3 years ago
8 0

Answer:

valence electrons

electron dot structures

Explanation:

Valence electrons -

It refers to the number of electrons that are present on the very last shell of any atom , is referred to as valence electrons .

Valence electrons are responsible to show any chemical properties of the atom .

Hence , the answer of the first part is - valence electrons .

Electron dot structures -

It is the structural representation , where the symbol of the element is placed at the center and the electrons are arranged surrounding it .

Hence , the answer of the second part is - electron dot structures .

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3 years ago
Determine ΔH for the reaction CaCO3 → CaO + CO2 given these data: 2 Ca + 2 C + 3 O2 → 2 CaCO3 ΔH = −2,414 kJ C + O2 → CO2 ΔH = −
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Answer:

The ΔH for the reaction is -456.5 KJ

Explanation:

Here we want to determine ΔH for the reaction;

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ΔH = ΔH(product) - ΔH(reactant)

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ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3)  ...........................(*)

From the other reactions, we can get the respective ΔH for the individual molecule in the reaction

In second reaction;

Kindly note that for elements, molecule of gases, ΔH = 0

What this means is that throughout the solution;

ΔH(Ca)  = 0 KJ

ΔH(O2) = 0 KJ

ΔH(C) = 0 KJ

Thus, in writing the equation for the subsequent chemical reactions, we shall need to write and equate the overall ΔH for the reaction to that of the product alone

So in the second reaction

ΔH = 2ΔH(CaCO3)

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-2414/2 = ΔH(CaCO3)

ΔH(CaCO3) = -1,207  KJ

Moving to the third reaction, we have;

ΔH = ΔH(CO2)

Hence ΔH(CO2) = -393.5 KJ

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ΔH = ΔH(CaO)

Hence ΔH(CaO) = -1270 KJ

Going back to equation *

ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3)

Using the values of the ΔH  of the respective molecules given above,

ΔH  = -1270 + (-393.5) - (-1207)

ΔH  = -456.5 KJ

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