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Lerok [7]
4 years ago
13

Find the median. 2, 20, 19, 15, 11, 9, 7, 1

Mathematics
1 answer:
Aliun [14]4 years ago
3 0
Put all the numbers in order, then it comes down to 11 and 9 divide by two and add. The answer is 10.
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Company A has three times as many customers as company B while company C has 10 customers more than company B. Let x represent t
Lostsunrise [7]

Answer:

x+2x+x+10

Step-by-step explanation:

Company A= x

Company B =2x

Company C =x+10

5 0
3 years ago
The variable x is twice the value of the variable y and the sum of x and y is 42 solve for x and y.
Oksi-84 [34.3K]

Write two equations with the given information:

1) x = 2y ( x is twice the value of y)

2) x + y = 42

Replace x in the second equation with the value of x in the first equation:

2y + y = 42

Simplify:

3y = 42

Divide both sides by 3:

y = 42 / 3

y = 14

Now we have the value for Y, solve for x by replacing y with 14:

x = 2y

x = 2(14)

x = 28

X = 28 and y = 14

4 0
3 years ago
Read 2 more answers
Is number 4 correct?
Strike441 [17]

Answer:

sure

Step-by-step explanation:

6 0
3 years ago
Write the equation of a linear function for which f=(-4)=0 and f=(0)=-2
densk [106]

Answer:

y = -0.5x - 2

Step-by-step explanation:

equation: f(x) = mx + b

f(-4) : -4m + b = 0  ...(1)

f(0):   0m + b = -2            b = -2   ... plug in (1)

-4m - 2 = 0

m = - 1/2 = - 0.5

linear equation: y = -0.5x - 2

6 0
3 years ago
A number of runners enter a race. The times that each runner finished is based on every hour. Five runners finished the race in
Aleksandr [31]

The histogram for the data is given at the end of this answer.

<h3>What is an histogram?</h3>

An histogram is a graph that shows the number of times each element of x was observed.

In this problem:

  • The elements of x are given by the time in hours.
  • The histogram shows the number of runners that finished the race in x hours.

Hence, the graph given at the end of this answer is the histogram.

You can learn more about histogram at brainly.com/question/2962546

3 0
3 years ago
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