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Neko [114]
3 years ago
11

How long does it take for sound to travel 28 miles

Physics
2 answers:
Sergeeva-Olga [200]3 years ago
5 0

Answer:

It takes roughly 140 seconds or roughly 2 minutes and 20 seconds for sound to travel 28 miles.

Explanation:

So, sound travels 1 mile in roughly 5 seconds.

To find out how long it takes for sound to travel 28 miles, multiply 28 by 5 (I'm pretty sure you know math!) So it takes roughly 140 seconds or roughly 2 minutes and 20 seconds for sound to travel 28 miles. (Remember! This is according to math, not science!) I hope you are safe! (Because this has been written during the corona virus times.) Please stay at home! =)

rewona [7]3 years ago
3 0

Answer:

i think near like 8 seconds i might be wrong

Explanation:

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if a runners power is 400 watts as she runs, how much chemical energy does she convert into other forms in 10 minutes
AnnZ [28]

Answer:

Energy converted = 240000\,Joules = 240\, kJoules

Explanation:

Recall that Power is the rate at which energy is transferred therefore defined by the mathematical formula: Power\,=\,\frac{Energy\,transferred}{time}

Since the information on the power of the runner is given, as well as the time the energy conversion takes place, we can then use this equation to find how much energy is been converted. Notice that we just need to change the given time *10 minutes) into the appropriate units  (seconds)to get the answer in SI units of energy (Joules). The conversion of 10 minutes into seconds is done by multiplying : 10 minutes * 60 seconds/minute = 600 seconds.

We use this then to find the energy converted by the runner:

Power\,=\,\frac{Energy\,transferred}{time}\\400 \,W = \frac{E}{600\,sec} \\400 \,W * 600\,sec=E\\E=240000\,Joules = 240\, kJoules

3 0
3 years ago
if the coefficient of linear expansion of a metal is 2.05× 10^-6 k^-1 what will be its new length if 50cm metal went through a t
boyakko [2]

Answer:

L = L0 (1 + c T)   where c is the coefficient and T the change in temperature

L = 50 ( 1 + 2.05E-6 * 50) = 50.0051 cm

7 0
3 years ago
A 0.150 kg ball on the end of a 1.10 m long cord (negligible mass)is swung in a vertical circle..
Aneli [31]
<span> For any body to move in a circle it requires the centripetal force (mv^2)/r. In this case a ball is moving in a vertical circle swung by a mass less cord. At the top of its arc if we draw its free body diagram and equate the forces in radial direction to the centripetal force we get it as T +mg =(mv^2)/r T is tension in cord m is mass of ball r is length of cord (radius of the vertical circle) To get the minimum value of velocity the LHS should be minimum. This is possible when T = 0. So minimum speed of ball v at top =sqrtr(rg)=sqrt(1.1*9.81) = 3.285 m/s In the second case the speed of ball at top = (2*3.285) =6.57 m/s Let us take the lowest point of the vertical circle as reference for potential energy and apllying the conservation of energy equation between top & bottom we get velocity at bottom as 9.3m/s. Now by drawing the free body diagram of the ball at the bottom and equating the net radial force to the centripetal force T-mg=(mv^2)/r We get tension in cord T=13.27 N</span>
3 0
3 years ago
Read 2 more answers
What causes spring and neap tides, rotation or revolution
jasenka [17]
Rotation causes them
7 0
3 years ago
. A stationary mass explodes into two parts of mass 4 kg and 40 kg . If the K.E of larger mass is 100 J . The K.E of small mass
alisha [4.7K]

Answer:

10J

Explanation:

KE = (1/2)mv²

100J = (.5)(40kg)v²

v²=(100J)/(20kg)

v²= 5

KE = 5(.5)(4kg)

KE = 10J

3 0
3 years ago
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