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4 years ago

How long does it take for sound to travel 28 miles

Physics

2 answers:

Sergeeva-Olga [200]4 years ago

5 0

Answer:

It takes roughly 140 seconds or roughly 2 minutes and 20 seconds for sound to travel 28 miles.

Explanation:

So, sound travels 1 mile in roughly 5 seconds.

To find out how long it takes for sound to travel 28 miles, multiply 28 by 5 (I'm pretty sure you know math!) So it takes roughly 140 seconds or roughly 2 minutes and 20 seconds for sound to travel 28 miles. (Remember! This is according to math, not science!) I hope you are safe! (Because this has been written during the corona virus times.) Please stay at home! =)

rewona [7]4 years ago

3 0

Answer:

i think near like 8 seconds i might be wrong

Explanation:

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3 years ago

Give an example of Newton's 1st law

Vesna [10]

Answer:

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Explanation:

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3 years ago

I need the answer please help

timurjin [86]

Answer:

A) Inertia

Explanation:

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3 years ago

Read 2 more answers

An alpha particle travels at a velocity of magnitude 520 m/s through a uniform magnetic field of magnitude 0.034 T. (An alpha pa

Keith_Richards [23]

Answer:

(a) Magnetic force $F=38.584\times 10^{-19}N$

(b) Acceleration $a=5.846\times 10^8m/sec^2$

Explanation:

We have given velocity of alpha particle v = 520 m/sec

Magnetic field B = 0.034 T

Charge on alpha particle $q=3.2\times 10^{-19}C$

Mass of alpha particle $m=6.6\times 10^{-27}kg$

Angle between velocity and magnetic field 43°

(a) Force acting on the particle is equal to

$F=q(v\times B)=qvBsin\Theta$

$F=3.2\times 10^{-19}\times 320\times 0.034\times sin43^{\circ}$

$F=38.584\times 10^{-19}N$

(B) According to newton's law

F = ma. here m is mass and a is acceleration.

So acceleration

$a=\frac{F}{m}=\frac{38.584\times 10^{-19}}{6.6\times 10^{-27}}=5.846\times 10^8m/sec^2$

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3 years ago

Air at 20ºC with a convection heat transfer coefficient of 20 W/m2·K blows over a pond. The surface temperature of the pond is 2

dimulka [17.4K]

Answer:

The heat flux between the surface of the pond and the surrounding air is 60 W/ $m^{2}$

Explanation:

Heat flux is the rate at which heat energy moves across a surface, it is the heat transferred per unit area of the surface. This can be calculated using the expression in equation 1;

q = Q/A ...............................1

since we are working with the convectional heat transfer coefficient equation 1 become;

q = h ( $T_{sf} -T_{sd}$ ) ........................2