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Neko [114]
4 years ago
11

How long does it take for sound to travel 28 miles

Physics
2 answers:
Sergeeva-Olga [200]4 years ago
5 0

Answer:

It takes roughly 140 seconds or roughly 2 minutes and 20 seconds for sound to travel 28 miles.

Explanation:

So, sound travels 1 mile in roughly 5 seconds.

To find out how long it takes for sound to travel 28 miles, multiply 28 by 5 (I'm pretty sure you know math!) So it takes roughly 140 seconds or roughly 2 minutes and 20 seconds for sound to travel 28 miles. (Remember! This is according to math, not science!) I hope you are safe! (Because this has been written during the corona virus times.) Please stay at home! =)

rewona [7]4 years ago
3 0

Answer:

i think near like 8 seconds i might be wrong

Explanation:

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3 years ago
Give an example of Newton's 1st law​
Vesna [10]

Answer:

A ball moving until gravity pulls it back down to the ground

Explanation:

5 0
3 years ago
I need the answer please help
timurjin [86]

Answer:

A) Inertia

Explanation:

Inertia is why objects tend to resist changes in their motion. Like a rolling ball will keep rolling unless we try to add friction to it, which then would stop the ball.

3 0
3 years ago
Read 2 more answers
An alpha particle travels at a velocity of magnitude 520 m/s through a uniform magnetic field of magnitude 0.034 T. (An alpha pa
Keith_Richards [23]

Answer:

(a) Magnetic force F=38.584\times 10^{-19}N

(b) Acceleration a=5.846\times 10^8m/sec^2

(C) Speed will remain same

Explanation:

We have given velocity of alpha particle v = 520 m/sec

Magnetic field B = 0.034 T

Charge on alpha particle q=3.2\times 10^{-19}C

Mass of alpha particle m=6.6\times 10^{-27}kg

Angle between velocity and magnetic field 43°

(a) Force acting on the particle is equal to

F=q(v\times B)=qvBsin\Theta

F=3.2\times 10^{-19}\times 320\times 0.034\times sin43^{\circ}

F=38.584\times 10^{-19}N

(B) According to newton's law

F = ma. here m is mass and a is acceleration.

So acceleration

a=\frac{F}{m}=\frac{38.584\times 10^{-19}}{6.6\times 10^{-27}}=5.846\times 10^8m/sec^2

(c) As the magnetic force is always perpendicular to velocity so speed will remain same neither decreases nor increases.

4 0
3 years ago
Air at 20ºC with a convection heat transfer coefficient of 20 W/m2·K blows over a pond. The surface temperature of the pond is 2
dimulka [17.4K]

Answer:

The heat flux between the surface of the pond and the surrounding air  is<em> 60 W/</em>m^{2}<em> </em>

Explanation:

Heat flux is the rate at which heat energy moves across a surface, it is the heat transferred per unit area of the surface. This can be calculated using the expression in equation 1;

q = Q/A ...............................1

since we are working with the convectional heat transfer coefficient equation 1 become;

q = h (T_{sf} -T_{sd}) ........................2

where q is the  heat flux;

Q is the heat energy that will be transferred;

h is the convectional heat coefficient = 20 W/m^{2}.K;

T_{sf} is the surface temperature = 23^{o}C 23°C + 273.15  = 296.15 K;

T_{sd} is the surrounding temperature = 20^{o}C = 20°C + 273.15  = 293.15 K;

The values are substituted into equation 2;

q = 20 W/m^{2}.K (  296.15 K - 293.15 K)

q = 20 W/m^{2}.K ( 3 K)

q =  60 W/m^{2}

Therefore the heat flux between the surface of the pond and the surrounding air  is 60 W/m^{2}

3 0
4 years ago
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