All categories

3 years ago

What will happen when two neutral objects are rubbed together?

Physics

1 answer:

Neko [114]3 years ago

4 0

Answer:

I hope this will help you

Explanation:

When two neutral objects come into contact--especially in a dry environment--electrons can be knocked loose from one object and picked up by the other. The object that gains electrons becomes negatively charged, while the object that loses electrons becomes positively charged. Objects with like charges repel each other, while those with opposite charges attract each other. This phenomenon--in which objects acquire an electric charge and exert a force on one another--is what we call static electricity.

You might be interested in

When a carpenter shuts off his circular saw, the 10.0 inch diameter blade slows from 4250 rpm to 0.00 in 4.00 s. (a) What is the

MaRussiya [10]

Answer:

(a) $\alpha=-111.26rad/s$

(b) $s=4450.6in$

Explanation:

First change the units of the velocity, using these equivalents $1rev=2\pi rad$ and $1 min =60s$

$4250rpm(\frac{2\pi rad}{1rev})(\frac{1 min}{60 s} )=445.06rad/s$

The angular acceleration $\alpha$ the time rate of change of the angular speed $\omega$ according to:

$\alpha=\frac{\Delta \omega}{\Delta t}$

$\Delta \omega=\omega_i-\omega_f$

Where $\omega_i$ is the original velocity, in the case the velocity before starting the deceleration, and $\omega_f$ is the final velocity, equal to zero because it has stopped.

$\alpha=\frac{\Delta \omega}{\Delta t} =\frac{\omega_i-\omega_f}{4}\frac{0-445.06}{4} =\frac{-445.06}{4} =-111.26rad/s$

b) To find the distance traveled in radians use the formula:

$\theta = \omega_i t + \frac{1}{2} \alpha t^2$

$\theta = 445.06 (4) + \frac{1}{2}(-111.26) (4)^2=1780.24-890.12=890.12rad$

To change this result to inches, solve the angular displacement $\theta$ for the distance traveled $s$ ( $r$ is the radius).

$\theta=\frac{s}{r} \\s=\theta r$

$s=890.12(5)=4450.6in$

c) The displacement is the difference between the original position and the final. But in every complete rotation of the rim, the point returns to its original position. so is needed to know how many rotations did the point in the 890.16 rad of distant traveled:

$\frac{890.12}{2\pi}=141.6667$

The real difference is in the 0.6667 (or 2/3) of the rotation. To find the distance between these positions imagine a triangle formed with the center of the blade (point C), the initial position (point A) and the final position (point B). The angle $\gamma=\frac{2\pi}{3}=\frac{360^o}{3}=120$ is between the two sides known. Using the theorem of the cosine we can find the missing side of the the triangle(which is also the net displacement):

$c^2=a^2+b^2-2abcos(\gamma)$

$c^2=5^2+5^2-2(5)(5)cos(\frac{2\pi}{3} )\\c^2=25+25+25\\c^2=75\\c=5\sqrt{3}=8.66in$

4 0

4 years ago

You travel from Point A to Point B to Point C. What is your

Luba_88 [7]

Answer:

12m is your displacement

3 0

3 years ago

Read 2 more answers

True or false: Everything in the universe works with harmony because of balanced energy

Eduardwww [97]

Answer:

Explanation:

True

7 0

3 years ago

Read 2 more answers

1. What does a football player need to do to change the position of the football?

exis [7]

Answer:

Yes, since formations aren't mentioned at all in the rules, they can be adjusted. Sometimes when making a substitution, a coach will sub in a defender for an attacker/midfielder if the team is ahead and wants to protect their lead....

Explanation:

8 0

3 years ago

Consider again the civilization described in the previous question. (They live on a planet orbiting 10 AU from a close binary st

Veseljchak [2.6K]

Fysbsts dydbdysj dudgts offhand fidydh jdgdhd

6 0

3 years ago