How much heat is required to convert 0.3 kilogram of ice at 0°C to water at the same temperature?
2 answers:
<span>The amount of heat required to melt a substance at its melting point is given by
</span>
<span>
where m is the mass of the substance and Lf is its latent heat of fusion. During the phase change, the temperature of the substance does not change, and all the energy given to the substance is used to break the bonds between the molecules. In this problem, we have a block of ice of mass m=0.3 kg. The specific latent heat of ice is 334 kJ/kg: therefore, the amount of heat required to melt it is given by
</span>
<span>
So, the correct answer is A) 100375 J</span>
</span>
where m is the mass of the substance and Lf is its latent heat of fusion. During the phase change, the temperature of the substance does not change, and all the energy given to the substance is used to break the bonds between the molecules. In this problem, we have a block of ice of mass m=0.3 kg. The specific latent heat of ice is 334 kJ/kg: therefore, the amount of heat required to melt it is given by
</span>
So, the correct answer is A) 100375 J</span>
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Answer:
The tension in the rope is 41.38 N.
Explanation:
Given that,
Mass of bucket of water = 14.0 kg
Diameter of cylinder = 0.260 m
Mass of cylinder = 12.1 kg
Distance = 10.7 m
Suppose we need to find that,
What is the tension in the rope while the bucket is falling
We need to calculate the acceleration
Using relation of torque
Where, I = moment of inertia
= angular acceleration
...(I)
Here, F = tension
The force is
...(II)
Where, F = tension
a = acceleration
From equation (I) and (II)
Put the value into the formula
We need to calculate the tension in the rope
Using equation (I)
Put the value into the formula
Hence, The tension in the rope is 41.38 N.