Answer:
The conservation of energy should be used to answer this question.
a)
At the position where the spring is unstretched, the elastic potential energy of the spring is zero.

since
and
is equal to zero.

The roots of this quadratic equation can be solved by using discriminant.


We should use the positive root, so
x = 0.292 m.
b)
We should use energy conservation between the point where the spring is momentarily at rest, and the point where the spring is unstretched.

since the kinetic energy at point 2 and the potential energy at point 3 is equal to zero.

Explanation:
In questions with springs, the important thing is to figure out the points where kinetic or potential energy terms would be zero. When the spring is unstretched, the elastic potential energy is zero. And when the spring is at rest, naturally the kinetic energy is equal to zero.
In part b) the cookie slides back to its original position, so the distance traveled, x, is equal to the distance in part a). The frictional force is constant in the system, so it is quite simple to solve part b) after solving part a).
Answer:
Option A
Explanation:
Ast the force is equal and the diayance is equal the beam is also balanced
Answer:
x = 0.54 m
y = 0.058 m
Explanation:
m = mass of the bullet = 16 g = 0.016 kg
v = speed of bullet before collision = 240 m/s
M = mass of the pendulum = 3.6 kg
L = length of the string = 2.5 m
h = height gained by the pendulum after collision
V = speed of the bullet and pendulum combination
Using conservation of momentum
m v = (m + M) V
(0.016) (240) = (0.016 + 3.6) V
V = 1.062 m/s
Using conservation of energy
Potential energy gained by bullet and pendulum combination = Kinetic energy of bullet and pendulum combination
(m + M) g h = (0.5) (m + M) V²
(9.8) h = (0.5) (1.062)²
h = 0.058 m
y = vertical displacement = h = 0.058 m
x = horizontal displacement
horizontal displacement is given as
x = sqrt(L² - (L - h)²)
x = sqrt(2.5² - (2.5 - 0.058)²)
x = 0.54 m
The simplest way to do this is to set up equivalent fractions, like this-

=

Solve for x by using cross multiplication.
40*2.2= 88
1*x=88
x=88
Therefore, the boy weighs 88lbs.