Answer:
y = (x+3)^2 -1
Step-by-step explanation:
The vertex form of the equation is
y = a(x-h)^2 +k where (h,k) is the vertex
The vertex is (-3,-1)
y = a(x- -3)^2 -1
y = a(x+3)^2 -1
Pick another point (-2,0) and substitute it into the equation
0 = a(-2+3)^2 -1 to find a
0 =a(1)^2 -1
0 = a-1
1 = a
y = (x+3)^2 -1
See https://web2.0calc.com/questions/need-help-now_10.
I don't understand what you're asking, is there supposed to be a picture with the question?
Answer:
Construction of a perpendicular bisector through C
Step-by-step explanation:
i just did the problem and put in that answer on bakpax and got it right
