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BabaBlast [244]
3 years ago
12

What is an equation of a line with a slope -2/3 and a y intercept of -4 ?

Mathematics
1 answer:
Gnesinka [82]3 years ago
6 0
Written in slope intercept form y=mx+b.......m is the slope.......b is the y intercept or where the line crosses the y axis

y=-2/3x - 4
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Help asap<br> 7. What is the domain and range of each function?<br><br> y=x^2<br><br> y=-x^2+2
Kipish [7]
Domain is all real Numbers
Range is all numbers over 0 - (0,
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7 0
3 years ago
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NY DMV Knowledge Test / Class D at Home
natima [27]

Answer: A

Step-by-step explanation: This sign should be shown one-half a mile before the working area, just in case they have to detour to another route.

4 0
3 years ago
Please help. Not sure how to do this one
Sladkaya [172]

The correct answer is: Option 3: (hofog)(x)=\frac{x-14}{x+4}

Step-by-step explanation:

Given

f(x)=\frac{x-6}{x}\\g(x)=x+4\\h(x)=3x-2

We have to find

(hofog)(x)

This will be equal to:

h(f(g(x)))

So we have to find the composition of (fog)(x) first

(fog)(x) = f(g(x))\\=\frac{x+4-6}{x+4}\\=\frac{x-2}{x+4}

Now,

(hofog)(x)=h(f(g(x)))\\=3(\frac{x-2}{x+4})-2\\=\frac{3x-6}{x+4}-2\\=\frac{3x-6-2(x+4)}{x+4}\\=\frac{3x-6-2x-8}{x+4}\\=\frac{x-14}{x+4}

The correct answer is: Option 3: (hofog)(x)=\frac{x-14}{x+4}

Keywords: Composition, Functions

Learn more about function composition at:

  • brainly.com/question/10015690
  • brainly.com/question/10048445

#LearnwithBrainly

8 0
3 years ago
Find the value of the integral that converges.<br> ∫^-5_-[infinity] x^-2 dx.
Bingel [31]

Answer:

\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}

Because the \lim_{x\to -\infty} \frac{1}{x} =0

The integral converges to \frac{1}{5}

Step-by-step explanation:

For this case we want to find the following integral:

\int_{-\infty}^{-5} x^{-2}dx

And we can solve the integral on this way:

\int_{-\infty}^{-5} x^{-2}dx= \frac{x^{-2+1}}{-2+1} \Big|_{-\infty}^{-5}

\int_{-\infty}^{-5} x^{-2}dx= -\frac{1}{x} \Big|_{-\infty}^{-5}

And if we evaluate the integral using the fundamental theorem of calculus we got:

\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}

Because the \lim_{x\to -\infty} \frac{1}{x} =0

The integral converges to \frac{1}{5}

8 0
3 years ago
Podría alguien ayudarme, es para mañana.
Ludmilka [50]

Answer:..$.$!:

Step-by-step explanation:

5 0
3 years ago
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