0.0179 ohms for copper.
0.0184 ohms for annealed copper
Ď = R (A/l) where
Ď = electrical resistivity
R = electrical resistance of a uniform specimen
A = cross sectional area
l = length
Solve for R by multiplying both sides by l/A
R = Ď(l/A)
The cross section of the wire is pi * 1^2 mm = 3.14159 square mm = 3.14159e-6 square meters.
The length is 3 meters. So l/A = 3/3.14159e-6 = 9.5493e5
Ď for copper is 1.68e-8 so 1.68e-8 * 9.5493e5 = 1.60e-2 ohms at 20 C
But copper has a temperature coefficient (α) of 0.00386 per degree C.
So the resistance value needs to be adjusted based upon how far from 20 C the temperature is.
50 - 20 = 30 C
So 0.00386 * 30 = 0.1158 meaning that the actual resistance at 50 C will be 11.58% higher.
So 1.1158 * 0.016 = 0.0179 ohms.
If you're using annealed copper, the values for Ď and the temperature coefficient change.
Ď = 1.72e-8
α = 0.00393
Doing the math, you get
1.72e-8 * 9.5493e5 * (1 + 30 * 0.00393) = 0.0184 ohms
Answer:
Force, 
Explanation:
Given that,
A potential energy function for a system in which a two-dimensional force acts is of the form of :
We need to find the force that acts at the point (x, y). The force in 2 dimensional with components is given by :
So, the force acting at the point (x,y) is 
. Hence, this is the required solution.
Since an alpha particle has 2 protons and no negative particles (electrons) to balance the net charge, its charge is
Q=2(1.6e-19)=3.2e-19C.
The force on a charged particle is F=QE so
(3.2e-19C)(600N/C)=1.92e-16N
ANSWER AND EXPLANATION:
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INFORMATION
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Frequency - 50Hz. Which means that the time period of the wave if 1/50 = 0.02 sec. Here we are going to check the average voltage for the time interval of 0.01sec. If the interval lies between π/2 to 3π/2. the average voltage will be zero. In all the other cases it will not be zero
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ANSWER
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So, the answer will be <u><em>may be zero. </em></u>
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Answer:
50 Km
Explanation:
If the car moved 50 km north and then 50 south its displacement would be 0. if it go in a direction like sw or ne or nw
