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kobusy [5.1K]
3 years ago
5

An AC source is rated 220 V, 50 Hz. The average voltage is calculated in a time interval of o.01 s. It (A) must be zero (C) is n

ever zero (B) may be zero (D) is (220W2)V.
Physics
1 answer:
dimaraw [331]3 years ago
6 0

ANSWER AND EXPLANATION:

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                                                 INFORMATION

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Frequency - 50Hz. Which means that the time period of the wave if 1/50 = 0.02 sec. Here we are going to check the average voltage for the time interval of 0.01sec. If the interval lies between π/2 to 3π/2. the average voltage will be zero. In all the other cases it will not be zero

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                                                    ANSWER

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                              So, the answer will be <u><em>may be zero. </em></u>

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HOPE THIS HELPS PLEASE MARK ME BRAINLIEST THANK YOU!

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I know that the PE will be the same for all the objects, but other then that I'm confused on what is correct and what isn't. ​
joja [24]

Answer:

Neither aspects of Dominique are correct.

Explanation:

They will not have the same speed before hitting the ground.

The block C has an initial horizontal velocity v₀ₓ , therefore the total ultimate speed before hitting the ground is  v = √ v₀ₓ² + vy²

It didn't matter how the blocks were dropped, they all landed at the same time. If any block has an initial vertical velocity it will have a higher end velocity. If Dominique means dropped from the rest then the previous claim is true. It is important how they were dropped.

The Dominique must said : The vertical speed will be the same because of conservation of energy.

The fact is,  they all landed at the same time and that is true. And it is important how they are thrown away.

God is with you!!!

7 0
3 years ago
A car travelled a distance of 200 m with initial velocity of 216 km/hr. Calculate the acceleration
pogonyaev

Answer:

a = 16\ m/s^2

Explanation:

When the velocity changes uniformly, the object has a constant acceleration. The acceleration, the velocities, and the distance are related by the equation:

v_f^2=v_o^2+2ax

Where:

vf = final velocity

vo = initial velocity

a = acceleration

x = distance

Solving for a:

\displaystyle a=\frac{v_f^2-v_o^2}{2x}

The car travels a distance of x=200 m and the velocities are:

vo = 216 Km/h

vf = 360 Km/h

Both velocities must be converted to meters by seconds.

vo = 216 Km/h *1000/3600 = 60 m/s

vf = 360 Km/h *1000/3600 = 100 m/s

The acceleration is:

\displaystyle a=\frac{100^2-60^2}{2*200}

\displaystyle a=\frac{10000-3600}{400}

\displaystyle a=\frac{6400}{400}

\mathbf{a = 16\ m/s^2}

7 0
3 years ago
The moon Phobos orbits Mars
Soloha48 [4]

Answer:

Explanation:

We are basically needing to solve for the time in the equation d = rt, where d is the distance around Mars (aka the circumference), r is the velocity, and t is time. We need to find the circumference and the velocity. We will begin with the velocity.

Because the gravitational attraction between Phobos and Mars provides the centripetal acceleration necessary to keep Phobos in its (sort of) circular path, the equation we use for this is:

F_g=F_c which says that Force supplied by gravity is equal to the centripetal force. Expanding that:

\frac{Gm_{Phobos}m_{Mars}}{r^2}=\frac{m_{Phobos}v^2}{r}

When we move that around mathematically to solve for the velocity value, what we end up with is:

v=\sqrt{\frac{Gm_{Mars}}{r} and filling in:

v=\sqrt{\frac{(6.67*10^{-11})(6.42*10^{23})}{9.38*10^6} } and we get that

v = 2100 m/s

Now for the circumference:

C = 2πr and

C = 2(3.1415)(9.38 × 10⁶) so

C = 5.9 × 10⁷

Putting that all together in the C = vT equation:

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8 0
3 years ago
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timama [110]

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And we need to express it in kg/m^{3}, knowing:

1 ml= 1 cm^{3}

1 m^{3}= (100 cm) ^{3}

1g = 1000 mg

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Hence:

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5 0
4 years ago
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C.

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6 0
4 years ago
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