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Daniel [21]
3 years ago
10

Find the electric force acting on an alpha particle in a horizontal electric field of 600N/C

Physics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0
Since an alpha particle has 2 protons and no negative particles (electrons) to balance the net charge, its charge is
Q=2(1.6e-19)=3.2e-19C.
The force on a charged particle is F=QE so
(3.2e-19C)(600N/C)=1.92e-16N
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Answer:

25/30 = 5/6 m/s^2 5/6 meters per second squared

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You are holding one end of an elastic cord that is fastened to a wall 3.0 m away. You begin shaking the end of the cord at 2.3 H
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Answer:

Time take to fill the standing wave to the entire length of the string is 1.3 sec.

Explanation:

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Standing wave is the example of the transverse wave, standing wave doesn't transfer energy in a medium.

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∴ v = fλ

Where v = speed of the standing wave.

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where t = time take to fill entire length of the string.

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⇒   t = \frac{3}{2.3} sec

     t = 1.3sec

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A 0.20-kg mass is oscillating on a spring over a horizontal frictionless surface. When it is at a displacement of 2.6 cm for equ
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Explanation:

The given data is as follows.

                    mass = 0.20 kg

              displacement = 2.6 cm

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       Spring potential energy = 2.2 J

Now, we will calculate the total energy present present as follows.

         Total energy = Kinetic energy + spring potential energy

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                            = 3.6 Joules

As maximum kinetic energy of the object will be equal to the total energy.

So,      K.E = Total energy

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Also, we know that

                  K.E = \frac{1}{2}mv^{2}_{m}

or,                   v = \sqrt{\frac{2K.E}{m}}

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