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KatRina [158]
2 years ago
12

In an exciting game, a baseball player manages to safely slide into second base. The mass of the baseball player is 88.1 kg and

the coefficient of kinetic friction between the ground and the player is 0.50. find the magnitude of the frictional force?
Physics
1 answer:
zlopas [31]2 years ago
7 0

Answer:

f=431.69\ N

Explanation:

Given:

  • mass of the player, m=88.1\ kg
  • coefficient of kinetic friction between the ground and the player, \mu_k=0.5
  • Since the normal reaction force on the player due to its mass will be equal to the weight of the player.

<u>We have the expression of kinetic friction as:</u>

f=\mu_k.N

here:

N = normal reaction force

f=0.5\times (88.1\times 9.8)

f=431.69\ N

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eduard

Answer:

A

Explanation:

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5 0
3 years ago
A circular loop of wire with a radius of 15.0cm and oriented in the horizontal xy-plane is located in a region of uniform magnet
Drupady [299]

Answer:

See answer

Explanation:

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A = \pi r^2

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\phi = \int \vec{B} \cdot d\vec{A}

d\vec{A} is parallel to \vec{B} and \vec{B} is constant in magnitude and direction therefore:

\phi = \int \vec{B} \cdot d\vec{A}= \int BdAcos(0)= B\int dA= B*(\pi r^2)= \pi Br^2

Part A)

initially the flux is \phi =\pi B r^2

after the interval \Delta t= 2.4 [m/s]

the flux is

\phi = 0

now, the EMF is defined as:

\epsilon =- \frac{d \phi}{dt},

if we consider \Delta t= 2.4 [m/s] very small then we can re-write it as:

\epsilon =- \frac{\Delta \phi}{\Delta t}

\Delta \phi = 0 - \pi B r^2=-\pi (1.7) (0.15)^2=-0.12

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Part B)

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3 years ago
A 5.6 g marble is fired vertically upward using a spring gun. The spring must be compressed 6.4 cm if the marble is to just reac
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Answer: im not gonna give i to you just do 15+15=_+ 5.6+6.4 easy

Explanation: i took the test and got a 100%

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Explanation:)

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2 years ago
I'm not really sure how to go about creating the equation, can anyone help me?
AlexFokin [52]
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\vec{r} =At\hat{i}+A[t^{3}-6t^{2}]\hat{j}

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