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2 years ago

9

The county planning department designs a new park in the shape of a parallelogram. They put in two diagonal walkways. What would

be the coordinates of the intersection of the diagonal walkways?

1 answer:

hjlf2 years ago

6 0

Answer:

yeet

hx for the thing idk

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8090 [49]

Answer: B

Step-by-step explanation:

The range of a function is the set of all possible values for the function's dependent variable. In this case, that variable is y, so we can look at the graph to observe what possible y-values fit in the range.

There are no y-values below -1 on the chart, and the function goes upwards to infinity, so the correct answer is B, y is greater than or equal to -1.

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2 years ago

A line passes through the points (5, –7.5) and has a y-intercept of 10.

brilliants [131]

Answer:y=0.5x+10

Step-by-step explanation:

need help with explanation?

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2 years ago

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Vika [28.1K]

Answer:

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2 years ago

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Which rectangle is not an enlargement of rectangle A?<br> ОА<br> ОВ<br> ОС<br> OD

soldier1979 [14.2K]

Answer: D

Step-by-step explanation:

Triangle D is not a enlargement of Triangle A because it is not the same type of number. 3 is an odd number, while 60 is an even number. The answer is D.

Hope this helps!

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2 years ago

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Evaluate the integral ∫2−1|x−1|dx

defon

I think you might be referring to the definite integral,

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx$

Recall the definition of absolute value:

$|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

Then $|x-1|=x-1$ if $x\ge1$ , and $|x-1|=1-x$ is $x$ . So spliting up the integral at <em>x</em> = 1, we have

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \int_{-1}^1(1-x)\,\mathrm dx + \int_1^2(x-1)\,\mathrm dx$

The rest is simple:

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \left(x-\dfrac{x^2}2\right)\bigg|_{-1}^1 + \left(\dfrac{x^2}2-x\right)\bigg|_1^2 \\\\ = \left(\left(1-\frac12\right)-\left(-1-\frac12\right)\right) + \left(\left(2-2\right)-\left(\frac12-1\right)\right) \\\\ = \boxed{\frac52}$

5 0

2 years ago