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Flauer [41]
2 years ago
12

What do u add to 5 5/8 to make 9 ?

Mathematics
2 answers:
mixas84 [53]2 years ago
8 0

Answer:

5+5=9and mark me as brainlestttt

zloy xaker [14]2 years ago
6 0

Answer:

27/8

Step-by-step explanation:

9 - 5 5/8 = 27/8

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Noah and Lin are marketing paper cones to hold popcorn to hand out at parent math night. They want the cones to hold 9 cubic inc
Vadim26 [7]

Answer: r = 1.69 inches

              h = 2.15 inches

Step-by-step explanation: Volume of a solid is the amount of space contained within a solid.

Volume of a cone is directly proportional to radius and height:

V=\frac{1}{3}\pi r^{2}h

They want the cones to hold the same volume of 9 cubic inches.

If height is 3:

9=\frac{1}{3}\pi r^{2}3

\pi r^{2}=9

r^{2}=2.864

r = 1.69 inches

When height is 3, radius is 1.69 inches for a cone to have 9 cubic inches of volume.

If radius is 2:

9=\frac{1}{3}\pi (2)^{2}h

h=\frac{9(3)}{4 \pi}

h = 2.15 inches

If radius is 2 inches, height of the cone is 2.15 inches.

6 0
3 years ago
Tan(x+pi/2)= negative cot x
DIA [1.3K]
I'm only going to alter the left hand side. The right side will stay the same the entire time

I'll use the identity tan(x) = sin(x)/cos(x) and cot(x) = cos(x)/sin(x)
I'll also use sin(x+y) = sin(x)cos(y)+cos(x)sin(y) and cos(x+y) = cos(x)cos(y)-sin(x)sin(y)

So with that in mind, this is how the steps would look:

tan(x+pi/2) = -cot x
sin(x+pi/2)/cos(x+pi/2) = -cot x
(sin(x)cos(pi/2)+cos(x)sin(pi/2))/(cos(x)cos(pi/2)-sin(x)sin(pi/2)) = -cot x
(sin(x)*0+cos(x)*1)/(cos(x)*0-sin(x)*1) = -cot x
(0+cos(x))/(-sin(x)-0) = -cot x
(cos(x))/(-sin(x)) = -cot x
-cot x = -cot x

Identity is confirmed

6 0
3 years ago
How many time 2/3 can go into 16<br><br> Explanation pls!!
tensa zangetsu [6.8K]

Answer:

24 times

Step-by-step explanation:

16 divided by 2/3 is 24

hope this helped!

7 0
1 year ago
PLZ help me fast 2 mins left
jek_recluse [69]

Answer:

\sqrt{-5}=i\sqrt{5}

\sqrt{-25}=5i

Step-by-step explanation:

i is an imaginary unit, this means

i^2=-1

Rewrite -5 as 5\cdot (-1)=5\cdot i^2,

then

\sqrt{-5}=\sqrt{5i^2}=\sqrt{5}\cdot \sqrt{i^2}=\sqrt{5}\cdot i=i\sqrt{5}

Rewrite -25 as -25=25\cdot (-1)=25\cdot i^2,

then

\sqrt{-25}=\sqrt{25\cdot i^2}=\sqrt{25}\cdot \sqrt{i^2}=5\cdot i=5i

6 0
2 years ago
AYOOO PLZ HELP ASAP!!!
tamaranim1 [39]

Answer:

B.

Step-by-step explanation:

Well we know that

224=2^{5} *7

so we can get the 2 outside of the radical

x^{11} =(x^{5} )^{2} *x

and we can get the x^2 outside too.

y^8=y^5*y^3

and we also can get y outside.

so we have:

2x^{2}y\sqrt[5]{7xy^3}

7 0
2 years ago
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