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Pepsi [2]
3 years ago
11

(a) Use a Riemann sum with m = n = 2 to estimate the value of the sin(x + y) dA R where R = [0, π] × [0, π]. Take the sample poi

nts to be lower left corners. (Round your answer to three decimal places.)
Mathematics
1 answer:
Kitty [74]3 years ago
3 0

Answer:

4.9361

Step-by-step explanation:

Rieman sum = ∫∫sin(x+y)ΔA

ΔA = ΔxΔy

Δx = \frac{π -0}{2}  = \frac{π}{2} = pi/2 = Δy

ΔA =  pi/2 * pi/2 = \frac{pi^{2} }{4}

Evaluating at the four corners

f(0,0) + f(0, pi/2) + f(pi/2,0)  + f(pi/2, pi/2) =

sin(0 +0) + sin(0 + pi/2) + sin(pi/2 + 0) + sin(pi/2 , pi/2) = 0 +1 + 1 + 0 = 2

∫∫sin(x+y)ΔA = 2 * \frac{pi^{2} }{4}  = \frac{pi^{2} }{2} = 4.9361

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4x + 6 - x = 7 + 2x

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3 years ago
Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From
maksim [4K]

Answer:

The 95% CI for the difference of means is:

-155.45 \leq \mu_1-\mu_2 \leq -44.55

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."</em>

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size:  4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

M_d=M_1-M_2=200-300=-100

The standard deviation can be estimated as:

\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45

The degrees of freedom are:

df=n_1+n_2-2=10+4-2=12

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55

8 0
3 years ago
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