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jenyasd209 [6]
3 years ago
10

Write the polynomial 4x^2 - 6x^6 + 2x^3 +12 - 5x^3 + 4x^4 in standard form

Mathematics
2 answers:
Fofino [41]3 years ago
5 0

Answer:

-6x^6 + 4x^4 - 3x^3 + 4x^2 + 12

Step-by-step explanation:

-6x^6 + 4x^4 - 5x^3 + 2x^3 + 4x^2 + 12

-6x^6 + 4x^4 - 3x^3 + 4x^2 + 12

wariber [46]3 years ago
5 0

Answer:

- 6x^6+ 4x^4 -3x^3+4x^2 +12

Step-by-step explanation:

4x^2 - 6x^6 + 2x^3 +12 - 5x^3 + 4x^4

WE need to write the polynomial in standard form

Standard form of the polynomial is the polynomial that start with highest exponent. Standard form has decreasing order of exponent.

-6x^6 is the highest exponent

now we write the terms with exponent decreasing order

4x^2 - 6x^6 + 2x^3 +12 - 5x^3 + 4x^4

4x^2 - 6x^6 + 2x^3 +12 - 5x^3 + 4x^4

First we combine like terms

4x^2 - 6x^6 -3x^3 +12 + 4x^4

- 6x^6+ 4x^4 -3x^3+4x^2 +12

The above polynomial is in standard form

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Answer:

6.25

Step-by-step explanation:

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Which of the equations will be a true statement if p=10 power of 3? Select all that apply.
Marat540 [252]

Answer:

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Step-by-step explanation:

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3 years ago
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Circle O has a circumference of 36tt cm. what is length of the radius r
allochka39001 [22]

Answer:

5.73cm

Step-by-step explanation:

Given parameters:

Circumference of the circle = 36cm

Unknown

Length of the radius = ?

Lets represent the radius by r

Solution

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Cos(−θ)=√3/3, sinθ<0
Delicious77 [7]

Answer:

\sin\theta=-\frac{\sqrt{6}}{3}


Step-by-step explanation:

The given trigonometric equation is \cos(-\theta)=\frac{\sqrt{3} }{3}.

We can either use the Pythagorean identity or the right angle triangle  to solve for \sin\theta.

According to the Pythagorean identity,

\cos^2\theta+\sin^2\theta=1


Recall that, the cosine function is an even function, therefore

\cos(-\theta)=\cos(\theta)


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We substitute this value in to the above Pythagorean identity to get;


(\frac{\sqrt{3}}{3})^2+\sin^2\theta=1


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\Rightarrow \sin^2\theta=1-\frac{3}{9}


\Rightarrow \sin^2\theta=\frac{6}{9}


\Rightarrow \sin\theta=\pm \sqrt{\frac{6}{9}}


\Rightarrow \sin\theta=\pm \frac{\sqrt{6}}{3}


But we were given that,

\sin\theta\:, so we choose the negative value.

\Rightarrow \sin\theta=-\frac{\sqrt{6}}{3}


The correct answer is B







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