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Stells [14]
3 years ago
13

What is the greatest possible product of a 2 digit number and a 1 digit number?

Mathematics
2 answers:
Law Incorporation [45]3 years ago
6 0
Largest 1-digit integer: 9
Largest 2-digit integer: 99
9 * 99 = 891
sladkih [1.3K]3 years ago
5 0
Highest 2-digit number = 99 
<span>Highest 1-digit number = 9 </span>
<span>Highest possible sum from 2, 2-digit numbers = 198 </span>
<span>Highest possible sum from 2, 1-digit numbers = 18</span>
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5+|x+1|=0 how many solutions
Inga [223]
Minus 5 on each side

5+[×+1]=0
-5. -5

×+1=0
-1. -1

x = -1
4 0
3 years ago
The mean finish time for a yearly amateur auto race was 186.32 minutes with a standard deviation of 0.305 minute. The winning​ c
uranmaximum [27]

Complete Question

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.305 minute. The winning car, driven by Roger, finished in 185.85 minutes. The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

Find their respective z-scores.

 Who had the more convincing victory?

A. Roger​ had a more convincing victory because of a higher z-score.

B. Karen a more convincing victory because of a higher z-score.

C. Roger had a more convincing victory, because of a lower z-score.

D. Karen a more convincing victory because of a lower z-score.

Answer:

The correct option is  D

Step-by-step explanation:

From the question we are told that

  The mean of the current year  is  \mu_c =  186.32 \  minutes

   The standard deviation is  \sigma_c  =  0.305 \  minutes

   The time taken by  the winning car for the current year  is  x =  185.85 \ minutes

  The mean of the previous  year  is  \mu_p =  110.7 \  minutes

   The standard deviation the previous  year  is  \sigma_p  = 0.115  \  minutes

 The time taken by  the winning car for the previous year  is  y =   110.48 \ minutes    

Generally the z-score for current year is mathematically evaluated as

     z_c  =  \frac{x- \mu_c}{\sigma_c }

=>     z_c  =  \frac{ 185.85- 186.32}{0.305 }

=> z_c  = -1.536

Generally the z-score for previous year is mathematically evaluated as

     z_p  =  \frac{y- \mu_p}{\sigma_p }

=>     z_p  =  \frac{ 110.48-110.7}{0.115  }

=> z_p  = -1.913

From the value obtained we see that  z_p  <  z_c , Hence  Karen had a more convincing victory because of the lower z -score.

5 0
3 years ago
A boat, which moves at 29 miles per hour in water without a current , goes 825 miles upstream and 825 miles back again in 58 hou
Igoryamba

Answer:

  4 mph

Step-by-step explanation:

Travel time is proportional to distance and inversely proportional to speed. If c represents the speed of the current in miles per hour, an equation for the total trip time is ...

  825/(29 -c) +825/(29 +c) = 58 . . . . . . hours travel time

  825(29 +c) +825(29 -c) = 58(29 -c)(29 +c)

  58c² -928 = 0 . . . . . . . rearrange to standard form

  58(c -4)(c +4) = 0 . . . . factor

Values of c that satisfy this equation are 4 and -4. For the purpose here, we'll choose the positive solution.

The speed of the current is 4 miles per hour.

8 0
2 years ago
A dog is tied to a leash on a tree and the leash is 10 meters long. There is a bone 15 meters away but the dog easily gets the b
Alex17521 [72]

Answer:

One way the dog can easily reach the bone is given by the relationship between the dog, the tree, and the bone

The dog can easily reach the bone when the tree is between the the dog and the bone, and the dog was more than 5 meters behind the tree

Therefore the distance the dog can reach in the direction of the bone from its position behind the tree is more than 15 meters and the dog can easily get the bone while the leash is not harmed

Step-by-step explanation:

3 0
3 years ago
The total distance to be covered was 52 miles. If he cycled at a constant rate of 13 miles per hour, how much time did Ricky tak
QveST [7]
13 miles per hour means he will cover 13 miles in 1 hour.

therefore in 2 hours, 26 miles.    3 hours, 39 miles.  4 hours, 52 miles.

Or time = distance/speed

time = 52/13 = 4 hours
4 0
3 years ago
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