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labwork [276]
2 years ago
8

Need help will give brainliest :)​

Mathematics
2 answers:
PSYCHO15rus [73]2 years ago
8 0

Answer:

for the first chart: first 2, second 2.25, third 2.5, and fourth 2.875. for the second chart: first 2.5, second 2.5, third 2.5, and fourth 2.5. hope this helps. sorry if I am wrong.

Step-by-step explanation:

I was the one that texted it as a comment. When I saw the question first I didn't see the answer button available so sorry I am late.

Elina [12.6K]2 years ago
3 0

Answer:

what do you need help with? can you explain please

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 Every equilateral triangle consists of three equal sides and three congruent angles.
 Therefore, there can be a triangle with three equal sides (5 centimeters in this case).
 Answer:
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Write the equation of a line with slope 3 and y-intercept −3.
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The equation would be y = 3x-3




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(8×1017)÷(2×103)Give your answer in standard form.
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4 0
2 years ago
A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet
Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

L_{1} = 2W_{1}

Also, the area of the walkway of 2 feet wide is 448:

W_{2} = 2 ft

A_{T} = W_{2}*L_{2} = 448 ft^{2}

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

A_{T} = A_{1} + A_{w}    (1)          

The area of the pool is given by:

A_{1} = L_{1}*W_{1}        

A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}  (2)          

And the area of the walkway is:

A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}    (3)          

Where the length of the bigger rectangle is related to the lower rectangle as follows:                  

L_{2} = 4 + L_{1} = 4 + 2W_{1}   (4)        

By entering equations (4), (3), and (2) into equation (1) we have:

A_{T} = A_{1} + A_{w}

A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}                

448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}            

224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}

224 = W_{1}^{2} + 8 + 6W_{1}

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

L_{1} = 2W_{1} = 2*12 ft = 24 ft

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!                                                                                          

8 0
3 years ago
Jack buys a bag of 5 apples each equal in size he eat 1/2 of one Apple what fraction did he eat
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You have 4\frac{1}{2} apples left. 
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5 0
3 years ago
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