Solution :
95% confidence interval for the difference between the means of ACT scores between two schools, is given by :
![$[(\overline X_1 - \overline X_2)-ME, (\overline X_1 - \overline X_2)+ME]$](https://tex.z-dn.net/?f=%24%5B%28%5Coverline%20X_1%20-%20%5Coverline%20X_2%29-ME%2C%20%28%5Coverline%20X_1%20-%20%5Coverline%20X_2%29%2BME%5D%24)
M.E. , Margin of error,
= 9.222
s = 3.03
= 1.4
Therefore, 95% CI = [(25.90-27.70) - 1.4 , (25.90-27.70) + 1.4]
= [-3.2, -0.4]
Therefore, the lower bound is -3.2
Answer:
the third one
Step-by-step explanation:
it is function that contain four domain
Answer:
4,2,1
Step-by-step explanation:
Answer:
f>2 or f<-2
Step-by-step explanation:
f^2−9>−5
Add 9 to each side
f^2−9+9>−5+9
f^2 >4
Take the square root of each side, remembering to flip the sign of the inequality for the negative
f>2 or f<-2
