3 years ago

Consider the following function. f(x)=x^2+2x+1.

Mathematics

1 answer:

Gekata [30.6K]3 years ago

4 0

Answer:

A) x² + 2x + 6

B) x² + 2x - 7

C) ¼(x²+2x+1))

D) 6x²+12x+6

E) -x²-2x-1

Step-by-step explanation:

A) f(x) + 5 =x²+2x+1 + 5

= x² + 2x + 6

B) f(x)-8,=x^2+2x+1-8

= x² + 2x - 7

C) ¼f(x) = ¼(x²+2x+1)

D) 6f(x) = 6(x²+2x+1) = 6x²+12x+6

E) -f(x) = -(x²+2x+1) = -x²-2x-1

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Show work to above problem

Len [333]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
|a|\implies 
\begin{cases}
+a\\
-a
\end{cases}\implies \pm a\\\\
-------------------------------\\\\
(16x^2)^{\frac{1}{2}}\implies \pm\sqrt[2]{(16x^2)^1}\implies \pm\sqrt{4^2x^2}\implies \pm\sqrt{(4x)^2}\implies \pm 4x
\\\\\\
\begin{cases}
+4\\
-4
\end{cases}\implies |4x|$

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