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slavikrds [6]
3 years ago
9

What are the solutions of the equation

Mathematics
2 answers:
notka56 [123]3 years ago
7 0
X²+4x+4=25
x²+4x+4-25=0
x²+7x-3x-21=0
x(x+7)-3(x+7)=0
(x+7)×(x-3)=0
x+7=0
x-3=0

x=-7
x=3

so your answer is x=-7 x=3
TEA [102]3 years ago
5 0
The solutions will be:
X = -7
And
X = 3
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P(x)equals=​R(x)minus−​C(x). Given ​R(x)equals=59 x minus 0.3 x squared59x−0.3x2 and Upper C left parenthesis x right parenthesi
Deffense [45]

Answer:

P(x)=-0.3x^2+56x-14  

Step-by-step explanation:

The given functions are

R(x)=59x-0.3x^2

C(x)=3x+14

It is given that

P(x)=R(x)-C(x)

Substitute the values of given functions in the above equation.

P(x)=59x-0.3x^2-(3x+14)

P(x)=59x-0.3x^2-3x-14

Combine like terms.

P(x)=-0.3x^2+(59x-3x)-14

P(x)=-0.3x^2+56x-14  

Therefore, the required function is P(x)=-0.3x^2+56x-14   .

4 0
3 years ago
Please help me with this long division problem. Thank you :)
velikii [3]
I think the answer is 0.52
5 0
3 years ago
Read 2 more answers
a car uses 9.5 L petrol per 100km a) determine the rate in km/L b) how far can the car travel with 47,5L petrol c) how many litr
Lana71 [14]

Step-by-step explanation:

a) determine the rate in km/L

==> 9.5 L/100km = 10.526316 km/L

b) how far can the car travel with 475L petrol

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c) how many litres of petrol do they need to travel 350 km

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Liters per 100 km (l/100km)0.29

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6 0
2 years ago
A bag has 5 red marbles, 4 blue marbles, 8 green marbles, and 3 yellow
kozerog [31]

<u>Answer:</u>

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<u>Step-by-step explanation:</u>

Percentage: Green marbles/Total marbles

  • => 8/5 + 4 + 8 + 3
  • => 8/20

<u>Percentage formula:</u> \frac{a}{b} (100)<u />

  • => 8/20 x 100
  • => 8 x 5
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Hence, 40% of the total marbles are green.

Hoped this helped.

BrainiacUser1357

7 0
3 years ago
What would I have to do here? Somebody please help me! (Look at the bottom problem not the top)
Zinaida [17]
Alright, let's do this! If $25 is one fifth of how much the game system cost then, multiply 25 times 5. And you should get your answer. 
I hope this helps. 
8 0
3 years ago
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