Answer:
30°
Step-by-step explanation:
∠A + ∠B + ∠C = 180
∠B = ∠A + 20
∠C = 2 * ∠B
<A + (∠A + 20) + (2 * ∠B) = 180
<A + (∠A + 20) + (2 * (∠A + 20)) = 180
<A + (∠A + 20) + 2∠A + 40 = 180
4∠A + 60 = 180
4∠A = 120
∠A = 30
Answer:
y=7/4x+7
Step-by-step explanation:
Answer:
D. Class frequency divided by the total frequency.
Answer:
The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
Step-by-step explanation:
Let be
, where
is the stopping distance measured in metres and
is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.
The procedure to find the speed related to the given stopping distance is described below:
1) Construct the graph of
.
2) Add the function
.
3) The point of intersection between both curves contains the speed related to given stopping distance.
In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
Answer:
387
Step-by-step explanation:
6(4)³ + 3(1)²
6(64) + 3(1)
384 + 3
= 387