We find<span> the first derivative of the curve, and evaluate it at </span>x<span>=1 (which we will use to obtain the </span>slope<span> of the </span>line tangent<span> to the curve at (1,−1)). So we have a </span>point<span> on the </span>tangent line: (x0,y0<span>)=(1,−1) and the </span>slope<span> of the </span>line tangent<span> at that </span>point<span>: m=−13.</span>
It is 16x2-24x+9
So...you can put it into the form a2+2ab+b2=(a+b)^2
Answer:
(6, 0)
Step-by-step explanation:
There are a few different methods to solve system of equations. For this problem, you can use substitution by solving one of the equations for a variable and then substituting this expression into the other equation to solve for the remaining variable:
x - y = 6, add 'y' to both sides to solve for 'x': x - y + y = 6 + y or x = 6 + y
Using the expression '6 + y' for the value of 'x' in the second equation:
2x + 3y = 12 or 2(6+y) + 3y = 12 or 12 + 2y + 3y = 12 or 12 + 5y = 12
Subtract 12 from both sides: 12 + 5y - 12 = 12 - 12 or 5y = 0 so y = 0
Now that you know the value of 'y', you can solve for 'x':
x = 6 + 0 or x = 6
Put the values of 'x' and 'y' into an ordered pair: (6,0).
Step-by-step explanation:
a straight line can be drawn between any two points.
given any two distinct point there is a line that contains them.
Answer: Yes they are not equal
Step-by-step explanation: The first equation 6x=-5 comes out to x=-5/6 The second equation -1=6x+4 comes out to x=-5/6
