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emmasim [6.3K]
3 years ago
8

At what velocity does a 10kg book dropped from 5 meters hit the ground at?

Physics
1 answer:
erica [24]3 years ago
6 0

Answer:

10m

Explanation:

v²=u²+2as

=0²+2×10×5

=100

v =10m/s

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3 years ago
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Which symbol and unit of measurement are used for voltage?
Keith_Richards [23]

Answer:

I should be V or E I am not sure what you mean by unit.

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3 years ago
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Describe the contributions of Mathieu Orfila and Robert Christison to the field of toxicology
riadik2000 [5.3K]

Answer:

They developed a test for poisons in the human tissues

Explanation:

Around the 19th century, Mathieu Orfila and Robert Christison developed important tests that identified poisons in human tissues.

By so doing, they laid the foundation for what is now called forensic toxicology. This science attempts to identify poisons in human tissues especially by way of autopsies and forensic investigation.

Today forensic toxicology has expanded to include alcohol testing techniques as well as testing athletes for intake of performance enhancing substances.

6 0
3 years ago
2 kids are running down the hall at 2 m/s, one is 40kg and the other is 50kg (p=ma)
Georgia [21]

The net force acting on the two (2) kids is equal to 180 Newton.

<u>Given the following data:</u>

  • Mass of kid 1 = 40 kilogram.
  • Mass of kid 2 = 50 kilogram.
  • Acceleration = 2 m/s^2

To determine the net force acting on the two (2) kids:

First of all, we would calculate the total mass of the two (2) kids:

Total\;mass = 50+40

Total mass = 90 kg.

<h3>How to calculate net force.</h3>

In this exercise, you're required to calculate the magnitude of the net force that is acting on these two (2) kids running down the hall. Thus, we would apply Newton's Second Law of Motion.

Mathematically, Newton's Second Law of Motion is given by this formula;

Net\;force = mass \times acceleration

Substituting the given parameters into the formula, we have;

Net\;force = 90 \times 2

Net force = 180 Newton.

Read more on acceleration here: brainly.com/question/1121817

7 0
3 years ago
The spring constant, k, for a 22cm spring is 50N/m. A force is used to stretch the spring and when it is measured again it is 32
lutik1710 [3]

Answer:

5N

Explanation:

Given parameters:

Original length = 22cm

Spring constant, K  = 50N/m

New length = 32cm

Unknown

Force applied  = ?

Solution:

The force applied on a spring can be derived using the expression below;

   Force  = KE

 k is the spring constant

 E is the extension

  extension = new length - original length

  extension  = 32cm  - 22cm  = 10cm

convert the extension from cm to m;  

   100cm  = 1m;

    10cm will give 0.1m

So;

  Force  = 50N/m x 0.1m  = 5N

8 0
3 years ago
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