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3 years ago

14

The plane is flying with a velocity of 220m/s when it encounters a 45 m/s wind blowing same direction as the planes motion calul

ate the new velocity of the plane relative to the ground

1 answer:

Inga [223]3 years ago

5 0

Answer:

I have no idea

Explanation:

You might be interested in

A ball of mass M collides with a stick with moment of inertia I = βml2 (relative to its center, which is its center of mass). Th

ZanzabumX [31]

Answer:

Part a)

$v_2 = \frac{\frac{2\beta mL^2v_o}{d}}{(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})}$

Part b)

$v_1 = v_0 - \frac{m}{M}(\frac{\frac{2\beta mL^2v_o}{d}}{(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})})$

Explanation:

Since the ball and rod is an isolated system and there is no external force on it so by momentum conservation we will have

$Mv_o = M v_1 + m v_2$

here we also use angular momentum conservation

so we have

$M v_o d = M v_1 d + \beta mL^2 \omega$

also we know that the collision is elastic collision so we have

$v_o = (v_2 + d\omega) - v_1$

so we have

$\omega = \frac{v_o + v_1 - v_2}{d}$

also we know

$M v_o d - M v_1 d = \beta mL^2(\frac{v_o + v_1 - v_2}{d})$

also we know

$v_1 = v_o - \frac{m}{M}v_2$

so we have

$M v_o d - M(v_o - \frac{m}{M}v_2)d = \beta mL^2(\frac{v_o + v_o - \frac{m}{M}v_2 - v_2}{d})$

$mv_2 d = \beta mL^2\frac{2v_o}{d} - \beta mL^2(1 + \frac{m}{M})\frac{v_2}{d}$

now we have

$(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})v_2 = \frac{2\beta mL^2v_o}{d}$

$v_2 = \frac{\frac{2\beta mL^2v_o}{d}}{(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})}$

Part b)

Now we know that speed of the ball after collision is given as

$v_1 = v_o - \frac{m}{M}v_2$

so it is given as

$v_1 = v_0 - \frac{m}{M}(\frac{\frac{2\beta mL^2v_o}{d}}{(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})})$

3 0

3 years ago

lutik1710 [3]

The power of the engine is 320 W.

<u>Explanation:</u>

Power may be defined as the rate of doing work (or) work done per unit time. One unit of energy is used to do the one unit of work.

Power = Work done / Time taken

Given, Force = 80 N, height = 5 m , final velocity = 4 m/s

To calculate the power, we must know the time taken.

To find the time, use the distance and speed formula which is given by

Time = Distance / speed

Here distance = 5 m and speed = 4 m/s

Time = 5 / 4 = 1.25 s.

Now, Power = work done / time

= (F * d) / t = (80 * 5) / 1.25

Power = 320 W.

The standard unit of power is watt (W) which is joule per second.

4 0

3 years ago

How much work is done if 10 N is applied to a 5kg object for 10 meters if there is an opposing force of 5 N

BlackZzzverrR [31]

Answer:

50 J

Explanation:

The net force acting on the box is given by the algebraic sum of the two forces, so:

$F=10 N -5 N = 5 N$

The net work done on the box is equal to (assuming the net force is parallel to the displacement of the object)

$W=Fd$

where

F = 5 N is the net force on the object

d = 10 m is the displacement of the object

Substituting,

$W=(5 N)(10 m)=50 J$

5 0

3 years ago

In a nuclear reactor, the control rods are: A.made of graphite B.used to keep the reactor cool C.used to absorb free neutrons D.

algol13

I think its E. the control rods are used to control <span>the fission rate of uranium and plutonium. Hope this helps!! </span>

4 0

3 years ago

Read 2 more answers

A machine runs for 50 seconds with a steady power output of 100 watts. How many joules of work does the

liberstina [14]

Answer:

The answer to your question is when time = 50 s, work = 5000 J

when time = 90 s, work = 9000 J

Explanation:

Data

time = 50 s or 90 s

Power = 100 watts

Power is defined as the rate of work done per unit of time.

Power = Work / time

-Solve for Work

Work = Power x time

-Substitution

Work = 100 x 50

-Result

Work = 5000

2.-When time = 90 s

Work = 100 x 90

-Result

Work = 9000 watts

6 0

3 years ago