Answer:
Explanation:
There are 2 NH4 in the equation therefore just multiply the molarity of the total solution by 2. Aaaaaaaaaaaaaaaaaaaaaaaaaaaand listen to "She Blinded Me With Science" by Thomas Dolby! ;)
It is C.ti and o and you don’t have to make me brainlest
I think the correct answer is B
1) If we had excess Cl2, then limiting reagent is Al
so moles of Al will be the same as the moles of AlCl3 produced at the output
moles of Al = 23/27 = 0.8518 moles
2)If we had excess Al , then limiting reagent is Cl2
so moles of Cl2 will be the 3/2 times as the moles of AlCl3 produced at the output
moles of Cl2 = 28/71 = 0.394 moles
<span>hence moles of AlCl3 = 0.394*2/3 = 0.2629 moles</span>