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denis23 [38]
4 years ago
10

Which of the following terms refers to the number of moles of solute per liter of solution?

Chemistry
1 answer:
Anika [276]4 years ago
5 0
Molarity
Molarity is a unit used to express the concentration of a substance, and it is defined as the number of moles of solute per decimeter cubed (liter) of solvent.
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What is the correct sequence of eras of the geologic time scale in order from oldest to youngest ?
finlep [7]

Answer:

it would be the 3rd

Explanation:

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How many orbitals are there in the third shell (n=3)?
andrezito [222]
The third shell contanis one s orbital,three p orbitals and five d orbitals.Each orbital hold 2 electron so the total number of electron which can be accommodate in third shell are 18 electrons
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Convert mass to moles for both reactants.<br> 2.50g CuCl2<br> 0.50g Al
alexandr402 [8]

Answer:

Number of moles of Al = 0.02 mol

Number of moles of CuCl₂ = 0.02 mol

Explanation:

Given data:

Mass of CuCl₂ = 2.50 g

Moles of CuCl₂ = ?

Solution:

Formula:

Number of moles = mass / molar mass

Molar mass of CuCl₂  =  63.546 + 35.5 ×2

Molar mass of CuCl₂  =  134.546 g/mol

Now we will put the values in formula:

Number of moles = 2.50 g / 134.546 g/mol

Number of moles = 0.02 mol

Given data:

Mass of Al = 0.50 g

Moles of Al = ?

Solution:

Formula:

Number of moles = mass / molar mass

Molar mass of Al  =  27 g/mol

Now we will put the values in formula:

Number of moles = 0.50 g / 27 g/mol

Number of moles = 0.02 mol

6 0
4 years ago
When 2.50 g of an unknown weak acid (ha) with a molar mass of 85.0 g/mol is dissolved in 250.0 g of water, the freezing point of
baherus [9]
When dT = Kf * molality * i
                = Kf*m*i
and when molality = (no of moles of solute) / Kg of solvent
                               = 2.5g /250g x 1 mol /85 g x1000g/kg
                               =0.1176 molal
and Kf for water = - 1.86 and dT = -0.255
by substitution 
0.255 = 1.86* 0.1176 * i
∴ i = 1.166
when the degree of dissociation formula is: when n=2 and  i = 1.166
a= i-1/n-1 = (1.166-1)/(2-1) = 0.359 by substitution by a and c(molality) in K formula
∴K = Ca^2/(1-a)
     = (0.1176 * 0.359)^2 / (1-0.359)
     = 2.8x10^-3



5 0
3 years ago
If the mass of a material is 76 grams and the volume of the material is 16 cm3, what would the density of the material be? g/cm3
mafiozo [28]
4.8 g/cm3 with sig figs since it's mass/volume you divide 76 grams by 16 cm3
6 0
3 years ago
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