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nasty-shy [4]
3 years ago
8

Please help me I'm desperate!!!!!

Mathematics
2 answers:
kvasek [131]3 years ago
8 0
C. Is the answer .yw
Simora [160]3 years ago
5 0
C is the answer to the question
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Complete the table. This is due today.. (plzhelp)
maksim [4K]
One way to carry out this problem is to simply take the value that you already know, which is that 1/5 is 20 % and multiply it by 2 for 2/5 or 2 (1/5ths) and do this for all of them. There is a pattern that occurs for every increase in one out of denominator of 5.










5 0
3 years ago
Help me pls guys/girls
Kamila [148]

Answer:

 V = 9.828 * 10^7 mm^3

a= 9.828  b = 7

9,827,000  mm^3

Step-by-step explanation:

The volume of a rectangular prism is

V = l*w*h

V = 1.2 *10^3  * 3.9*10^2  * 2.1*10^2

We multiply the numbers out front and add the exponents  (the powers of 10)

V = (1.2*3.9*2.1)  * 10^(3+2+2)

 V = 9.828 * 10^7 mm^3

Rewriting this in standard form means moving the decimal 7 places to the left.  Since there is not enough places add zeros

9,827,000  mm^3

5 0
3 years ago
The Larger of two numbers is 27 more than the smaller. When added together , the sum of the larger number and five times the sma
Genrish500 [490]

Answer:

Small no. is 15

Larger no. is 15 + 27 = 42

Step-by-step explanation:

Let the small no. be x

Larger no. will be x + 27

5x + x + 27 = 117

6x + 27 = 117

6x = 117-27

x = 90/6

x = 15

4 0
3 years ago
Solve the equation
erastova [34]

Look at the picture.

|a|=\left\{\begin{array}{ccc}a&for&a\geq0\\-a&for&a < 0\end{array}\right\\\\|9-8x|=\left\{\begin{array}{ccc}9-8x&for&x\in\left(-\infty,\ \dfrac{9}{8}\right]\\-(9-8x)&for&x\in\left(\dfrac{9}{8},\ \infty\right)\end{array}\right

6 0
3 years ago
Write an equation in standard form for each line.
LenaWriter [7]

The standard form: Ax + By = C.

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}


7. We have the points (4, -7) and (2, -3). Substitute:

m=\dfrac{-3-(-7)}{2-4}=\dfrac{4}{-2}=-2\\\\y-(-7)=-2(x-4)\qquad|\text{use distributive property}\\\\y+7=(-2)(x)+(-2)(-4)\\\\y+7=-2x+8\qquad|-7\\\\y=-2x+1\qquad|+2x\\\\\boxed{2x+y=1}

8. We have the points (1, 5) and (-10, -6). Substitute:

m=\dfrac{-6-5}{-10-1}=\dfrac{-11}{-11}=1\\\\y-5=1(x-1)\\\\y-5=x-1\qquad|+5\\\\y=x+4\qquad|-x\\\\-x+y=4\qquad|\text{change the signs}\\\\\boxed{x-y=-4}


7 0
3 years ago
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