Use the trig identity
2*sin(A)*cos(A) = sin(2*A)
to get
sin(A)*cos(A) = (1/2)*sin(2*A)
So to find the max of sin(A)*cos(A), we can find the max of (1/2)*sin(2*A)
It turns out that sin(x) maxes out at 1 where x can be any expression you want. In this case, x = 2*A.
So (1/2)*sin(2*A) maxes out at (1/2)*1 = 1/2 = 0.5
The greatest value of sin(A)*cos(A) is 1/2 = 0.5
Answer:
the second and thrid one :)
Step-by-step explanation:
Answer:
The answer is d
Step-by-step explanation:
<span>Best you can do is describe a set:
John
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Answer:
- Slope: -2
- equation: y = -2x +5
Step-by-step explanation:
The given point is the y-intercept of the line, so the slope-intercept form of the equation of a line can be used:
y = mx + b . . . . for slope m and y-intercept b
Here, you have the slope given as ...
m = -2
y-intercept = 5
so the equation of the line is ...
y = -2x +5
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The y-intercept is the value of y when x=0. The point (x, y) = (0, 5) tells you the y-intercept is 5.