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jarptica [38.1K]
3 years ago
9

the curved surface of a cylindrical surface is 704 cm square calculate the height when the radius is 8cm​

Mathematics
1 answer:
AlexFokin [52]3 years ago
7 0

Answer:

CSA of cylinder = 704cm²

We know that

CSA of cylinder = 2πrh

or 2πrh = 704

or, 2*22/7 *8 *h = 704 ( since r=8cm)

or, 352h = 704*7

or, h = 4928/352 = 14cm

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2 years ago
Which table represents a linear function?
aliina [53]
In each table, x increases by 1. We start with x = 0 and stop with x = 3. So we will focus on the y columns of each table as those are different.

Let's move from left to right along the four tables.

For the first table, we go from y = 1 to y = 2. That's an increase of 1
Sticking with the first table, we go from y = 2 to y = 4. The increase is now 2
Since the increase is not the same, this means the table is not linear. The y increase must be constant. We can rule out choice A

Choice B can be ruled out as well. Why? Because...
the jump from y = 0 to y = 1 is +1
the jump from y = 1 to y = 3 is +2
The same problem comes up as it did with choice A

Choice C has the same problem, but the increase turns into a decrease half the time. We go from y = 0 to y = 1, then we go back to y = 0 so the "increase" is really a decrease. We can think of it as a negative increase. Regardless, this allows us to rule out choice C

Only choice D is the answer. Each time x goes up by 1, y goes up by 2. Therefore the slope is 2/1 = 2
4 0
3 years ago
Read 2 more answers
Sarah kicked a ball in the air. The function
Aleksandr-060686 [28]

Answer: The ball hits the ground at 5 s

Step-by-step explanation:

The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:

f=30 t- 6t^{2} (1)

Where f models the height of the ball in meters and t the time.

Now, let's find the time t when the ball Sara kicked hits the ground (this is when f=0 m):

0=30 t- 6t^{2} (2)

Rearranging the equation:

6t^{2}-30 t=0 (3)

Dividing both sides of the equation by 6:

t^{2}-5 t=0 (4)

This quadratic equation can be written in the form at^{2}+bt+c=0, and can be solved with the following formula:  

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} (5)  

Where:  

a=1  

b=-5  

c=0  

Substituting the known values:  

t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(0)}}{2(1)} (6)  

Solving we have the following result:

t=5 s  This means the ball hit the ground 5 seconds after it was kicked by Sara.

6 0
3 years ago
What is the slope of the line? ​
ozzi

Answer:

1/2

Step-by-step explanation:

6 0
3 years ago
If x = 9 units and h = 4 units, then what is the area of the triangle shown above?
Aleks04 [339]

Answer:

18

Step-by-step explanation:

The area of triangle is b*h/2

so it will be 36/2 which will be 18

Please mark as Brainliest

7 0
2 years ago
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