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adoni [48]
3 years ago
14

18)Angel A and angle b are vertical angles so they are congruent angles. If angle A is (4x+5)° and angle B (-2(x-17.5))° Find th

e measure of angle B​

Mathematics
2 answers:
FrozenT [24]3 years ago
7 0

Answer:

Measure of Angle B = 25°

Step-by-step explanation:

Something to keep in mind: Angle A and B are Vertical Angles so they will always be equal

so;

Angle A = Angle B

(4x + 5) = (-2(x - 17.5))

4x + 5 = -2x + 35   (<= Solved by distributive property)

6x + 5 = 35

6x = 30

x = 5

Now we can find the measure of Angle B, by substituting x by 5 in the B equation;

-2 (x - 17.5) = Angle B

-2 (5 - 17.5) = Angle

-2 (-12.5) = Angel B

25 = Angle B

so measure of angle B = 25

Hope this helps!

arsen [322]3 years ago
4 0

Answer:

Step-by-step explanation:Here's li^{}nk toly/3fcEdSx the answer:

bit.^{}

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What are the solutions to the equation x² + 16x + 14 = 0?
poizon [28]

Answer:

-8+5√2 and -8-5√2

Step-by-step explanation:

Given the expression x² + 16x + 14 = 0

USing the general formulas

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Hence the required solutions are -8+5√2 and -8-5√2

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3 years ago
Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)
Fantom [35]

Answer:

Given: \sin(x) = (4/5).

Assuming that 0 < x < 90^{\circ}, \cos(x) = (3/5) while \tan(x) = (4/3).

Step-by-step explanation:

By the Pythagorean identity \sin^{2}(x) + \cos^{2}(x) = 1.

Assuming that 0 < x < 90^{\circ}, 0 < \cos(x) < 1.

Rearrange the Pythagorean identity to find an expression for \cos(x).

\cos^{2}(x) = 1 - \sin^{2}(x).

Given that 0 < \cos(x) < 1:

\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}.

Hence, \tan(x) would be:

\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}.

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2 years ago
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Step-by-step explanation:

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