The slope of the line that is perpendicular to 6x + 2y = -32 is: 1/3.
<h3>What is the Slope of Perpendicular Lines?</h3>
The slope of two lines that are perpendicular to each other will always have a product that is equal to -1, which means that their slopes are negative reciprocals to each other.
Rewrite 6x + 2y = -32 in slope-intercept form:
2y = -6x - 32
2y/2 = -6x/2 - 32/2
y = -3x - 16
The slope is -3. Negative reciprocal of -3 is 1/3.
Therefore, the slope of the perpendicular line would be: 1/3.
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Hello!
As you can see this line is horizontal. It is 6 units long. Therefore the center is three units in. Therefore the center of this circle is at (1,2).
I hope this helps!
Note :- If sample size n > 30 OR Population standard deviation σ is given then We use Z test.
If sample size n < 30 AND Population standard deviation σ is unknown then we use t test.
In this question we are not given Population standard deviations σ1 and σ2.
Also n1 = 14 and n2 = 13 both sample sizes are LESS than 30.
Therefore we use t test.
Given :- Assume the population standard deviations are equal. ( σ1 = σ2)
then Degrees of freedom = n1 + n2 - 2 = 14 + 13 - 2 = 25.
(kindly find the image attached with this solution)
Answer :- Therefore 25 degrees of freedom are used to find the t critical value.
Answer:
y = - 2x + 6
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = 
with (x₁, y₁ ) = (1, 4 ) and (x₂, y₂ ) = (2, 2 )
m =
=
= - 2 , then
y = - 2x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (2, 2 ) , then
2 = - 4 + c ⇒ c = 2 + 4 = 6
y = - 2x + 6 ← equation of line
It would be 60. He sold his painting for 50 which was 10 less that the original price. So 50+10=60