A number greater than -5 written as a problem

There are 2 pigs, 1 cat, 3 goats, and 4 cows at the state fair. As people enter the barn area they are randomly given one animal

marshall27 [118]

Answer:

3/10

Step-by-step explanation:

Probability will be the number of goats, since goats is what you're looking for, over the number of total animals. So that gives 3/10.

To get that as a decimal, divide 3 by 10. Then take your decimal and multiply it by 100 to give the percent.

8 0

2 years ago

Please help me with this

son4ous [18]

Answer:

$72

Step-by-step explanation:

First yard:

weeded and mowed

12 + 20 = 32

Second yard:

mowed and edged

20+ 15 = 35

Then he got a tip of 5

Total

32+35+ 5

72

7 0

2 years ago

Read 2 more answers

What is the answer to -6.5 + 2.1

vladimir1956 [14]

-6.5 + 2.1
-4.4

Answer: -4.4

5 0

2 years ago

Read 2 more answers

Suppose $4000 is invested at 6% interest compounded annually. How much money will there be in the bank at the end of 5 years? At

sleet_krkn [62]

Answer: The accumulated amount after 5 years = $ 5352.90

The accumulated amount after 20 years = $ 12828.54

Step-by-step explanation:

Formula to find the accumulated amount after investing P amount at the rate of r ( in decimal) compounded annually for t years:

$A=P(1+r)^t$

As per given , we have

P = $4,000

r= 6% = 0.06

Put thsese values in formula : $A=4000(1+0.06)^t=4000(1.06)^t$

The accumulated amount after 5 years = $A(5)=4000(1.06)^5$

$=4000(1.3382255776)=5352.9023104\\\\\approx5352.90$

Hence, the accumulated amount after 5 years = $ 5352.90

The accumulated amount after 20 years = $A(20)=4000(1.06)^{20}$

$=4000(3.20713547221)=12828.5418888\\\\\approx12828.54$

Hence, the accumulated amount after 20 years = $ 12828.54

4 0

2 years ago

AT&T would like to test the hypothesis that the proportion of 18- to 34-year-old Americans that own a cell phone is less tha

Vera_Pavlovna [14]

Answer:

The null and alternative hypothesis can be written as:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of 18- to 34-year-old Americans that own a cell phone is less than the proportion of 35- to 49-year-old Americans.

This claim will be reflected in the alternnative hypothesis, that will state that the population proportion 1 (18 to 34) is significantly smaller than the population proportion 2 (35 to 49).

On the contrary, the null hypothesis will state that the population proportion 1 is ot significantly smaller than the population proportion 2.

Then, the null and alternative hypothesis can be written as:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

The significance level is assumed to be 0.05.

The sample 1, of size n1=200 has a proportion of p1=0.63.

$p_1=X_1/n_1=126/200=0.63$

The sample 2, of size n2=175 has a proportion of p2=0.68.

$p_2=X_2/n_2=119/175=0.68$

The difference between proportions is (p1-p2)=-0.05.

$p_d=p_1-p_2=0.63-0.68=-0.05$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{126+119}{200+175}=\dfrac{245}{375}=0.653$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.653*0.347}{200}+\dfrac{0.653*0.347}{175}}\\\\\\s_{p1-p2}=\sqrt{0.001132+0.001294}=\sqrt{0.002427}=0.049$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.05-0}{0.049}=\dfrac{-0.05}{0.049}=-1.01$

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

$\text{P-value}=P(z$

As the P-value (0.1554) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the proportion of 18- to 34-year-old Americans that own a cell phone is less than the proportion of 35- to 49-year-old Americans.

5 0

2 years ago