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Inessa05 [86]
3 years ago
7

The weekly salaries of a sample of employees at the local bank are given in the table below. Employee Weekly Salary Anja $245 Ra

z $300 Natalie $325 Mic $465 Paul $100 What is the variance for the data? Variance: mc006-1.jpg

Mathematics
2 answers:
lutik1710 [3]3 years ago
7 0

Answer:

the other guy got the answer right...he did a different question from edg enuity

Step-by-step explanation:

Setler [38]3 years ago
5 0
The mean of the data is given

\frac{245+300+325+465+100}{5}=287

The variance of the data is given
( \frac{245^{2}+300^{2}+325^{2}+465^{2}+100^{2}} {5})-(287^{2})96375- 287^{2} =14006
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Step-by-step explanation:

1.

(3,1) and\:perpendicular \:to \: y = -x+1\\(3,1) = (x,y)\\m = -1\\In\: perpendicularism ; m_2 = \frac{-1}{m_1} \\m_2 = \frac{-1}{-1} \\m_2 =1\\y = mx+c\\1 = 1(3) +c\\1=3+c\\1-3=c\\-2 =c\\Substitute \:new \:values\:into\\y =mx+c\\y = 1x -2\\y = x-2

2.

(-1,7) =(x_1,y_1)\\\\5y = 4x+5\\\\Write\:in\:y=mx+c\:form\\\frac{5y}{5} = \frac{4}{5} x + \frac{5}{5} \\y = \frac{4}{5} x +1\\m = \frac{4}{5} \\\\y -y_1=m(x-x_1)\\y-7=\frac{4}{5} (x -(-1)\\y -7 = 4/5(x+1)\\y -7 = 4/5x +4/5\\\\y = \frac{4}{5} x+\frac{4}{5} +7\\\\y = \frac{4}{5} x +39/5

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3 years ago
the length of a rectangle is 5cm greater than the width. the area of the rectangle is 84cm squared. find the length and width
Ymorist [56]

Answer:

Therefore,

Length=12\ cm

Width= 7\ cm

Step-by-step explanation:

Let the Width of rectangle be 'x' cm.

Then the length of a rectangle will be (x + 5) cm.

Area of rectangle given is 84 cm squared.

To Find:

Length = (x+5) = ?

Width = x = ?

Solution:

We have area of rectangle given as

\textrm{Area of Rectangle}=Length\times Width

Substituting the given values we get

84=(x+5)x\\x^{2} +5x-84=0\\

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Therefore,

Length=x+5=7+5=12\ cm

Therefore,

Length=12\ cm

Width= 7\ cm

8 0
3 years ago
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