96% of 25 is 24 hope this helps
Answer:
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Of the 2809 people who responded to survey, 1634 stated that they currently use social media.
This means that 
98% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
AP and BQ are medians of the triangle ABC and K is the centroid of the triangle.
One of the properties of the medians is that the point of intersection divides the median in the ratio 2:1
So BK = 2 KQ therefore
15 = 2 * KQ
and KQ = 7.5 answer
Answer:
-8 12 5
Step-by-step explanation:
they are the numbers attached to the variables