A population of rabbits oscillates 19 above and below average during the year, hitting the lowest value in january. the average
1 answer:
Answer:
Step-by-step explanation:
The initial value of the population is 650
Each year the population increases 160
The population oscillates 19 above and below.
Due to this information you can assume that the function is:
where for t=0 p(t)=650
where t=12 160/12 (12) = 160
you can assume that the sinusoidal function has a period of one month. Thus, the population oscillates several times in one year with an amplitu of the oscillation of 19. The, w is:
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Answer:
∠HGJ = 35°
Step-by-step explanation:
Although the question is somewhat incomplete, I have tried to reconstruct the question as much as possible to aid understanding (attached is the pictorial representation of the rhombus).
Firstly, it is important to note that rhombuses are parallelograms which have all sides equal and whose diagonals are perpendicular to each other. In addition to this, their diagonals bisect one other.
Mathematically, |EF| = |FG| = |GH| = |HE|
Another property which rhombuses have is that their opposite angles are equal.
Mathematically, ∠E = ∠G, ∠H = ∠F
The adjacent angles in a rhombus are supplementary. This means that the sum of angles closest to each other is 180°.
Mathematically, ∠E + ∠F = 180°, ∠F + ∠G = 180°, ∠G + ∠H = 180°,
∠H + ∠E = 180°
The question gave us ∠GHE and asked us to find ∠HGJ (denoted as θ in the picture attached). Note that ∠GHE means ∠H. That is, ∠GHE ⇒ ∠H
∠GHE or ∠H = 110°
From the properties of rhombuses (earlier stated), we know that adjacent angles in a rhombus are supplementary
Mathematically,
∠GHE + ∠FGH ⇒ 110° + ∠FGH = 180° ⇒ ∠FGH = 180° - 110°
∠FGH or ∠G = 70°
To calculate for ∠HGJ, we divide ∠FGH by 2, we have:
∠HGJ = ∠FGH ÷ 2 = 70° ÷ 2
∠HGJ = 35°
