2 cakes - Theresa's and Joe's
Theresa's cake had 6 pieces after she cut it. (2 times the size of Joe's pieces)
Joe's cake had 12 pieces after he cut it. (1/2 the size of Theresa's pieces)
We know that 8/12ths of ONE cake were eaten and that Joe ate 2 of his pieces.
We want to know how many pieces Theresa ate of her cake. Keeping in mind that her pieces are equal to 2 of Joe's pieces we can solve this question.
8/12 eaten total
if 2/12 by Joe
then 8-2 = 6, 6/12 by Theresa
(BUT: Theresa's pieces were twice the size of Joe's so we will divide by 2)
6/12 = 3/6
Answer: Theresa ate 3 pieces of her cake
Answer:
8/7
Step-by-step explanation:
8/7 because the numerator is greater than the denominator.
Answer:
Its Option C
Step-by-step explanation:
The difference is 180 - 135 = $45
So it is 45 * 100 / 135
= 33.33% greater
Step-by-step explanation:
SA=ph+2A, that is, perimeter × height+ twice area
p=21+20+29=70cm
h=22cm
70×22=1540cm
A=1/2 ×20×21=210×2=420
1540+420=1960cm2
Let y = the length of the 3rd side
x+3 + 2x+4 + y = 6x
x + 2x + 3 + 4 + y = 6x
3x + 7 +y = 6x
7 + y = 3x
y = 3x - 7
The length of the third side in terms of x is 3x-7
